A) Yes. we don't have enough information so this can not be determined.
B) No, it would just be an outlier.
If you mean to the nearest HUNDREDTH the answer is 14.60.
<span>Table:
Class Boundaries Frequency
5-10 8
10-15 9
15-20 15
20-25 10
25-30 8
30-35 6
----------
total 56
Average =
[5+10]/2*8+[10+15]/2*9+[15+20]/2*15+[20+25]/2*10+[25+30]/2*8+[30+35]/2*6
---------------------------------------------------------------------------------------------------
</span> 56
That is 1075 / 56 = 19.2
Answer: 19
Haileys work is correct so B should be the right answer
Answer:
(-2,-1) is where u start
Step-by-step explanation: