Answer:
shown in the attachment
Explanation:
The detailed step by step and necessary mathematical application is as shown in the attachment.
A flashlight has a resistance of 30 Q and is connected
1 answer:
Answer:
3 A
Explanation:
The relationship between voltage, current and resistance in a conductor is expressed by Ohm's law, which states that:
where:
V is the potential difference across the conductor
R is the resistance of the conductor
I is the current flowing through it
In this problem, for this flashlight we have:
V = 90 V is the potential difference
is the resistance of the flashlight
Solving for I, we find the current:
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Answer:
- the power to the air is 850 MW
- mass flow rate of the air is 84577.11 kg/s
Explanation:
Given the data in the question;
Net power generated; = 150 MW
Heat input; = 1000 MW
Power to air = ?
For closed cycles
Power to air Q₀ = Heat input; - Net power generated;
we substitute
Power to air Q₀ = 1000 - 150
Q₀ = 850 MW
Therefore, the power to the air is 850 MW
given that ΔT = 10 °C
mass flow rate of air required will be;
⇒ Q₀ / CpΔT
we know that specific heat of air at p=c ; Cp = 1.005 kJ/kg.K
we substitute
⇒ ( 850 × 10³ ) / [ 1.005 × 10 ]
⇒ ( 850 × 10³ ) / 10.05
⇒ 84577.11 kg/s
Therefore, mass flow rate of the air is 84577.11 kg/s