Question

A flashlight has a resistance of 30 Q and is connected

Answer 1

Answer:

3 A

Explanation:

The relationship between voltage, current and resistance in a conductor is expressed by Ohm's law, which states that:

$V=RI$

where:

V is the potential difference across the conductor

R is the resistance of the conductor

I is the current flowing through it

In this problem, for this flashlight we have:

V = 90 V is the potential difference

$R=30 \Omega$ is the resistance of the flashlight

Solving for I, we find the current:

$I=\frac{V}{R}=\frac{90}{30}=3 A$