8 miles per hour
because if it is moving at 4 miles every half hour that means you have to multiply it by two to get it in miles per hour and we all know that 4 times 2 is 8 so it would be 8 miles per hour =)
Answer:
Distance = 7 meters.
Explanation:
Given the following data;
Force = 50N
Kinetic energy = 350J
To find the distance;
We know that energy possessed by an object over a distance represents the work done by the object.
Mathematically, work done is given by the formula;
Workdone = force * distance
Substituting into the formula, we have;
350 = 50 * distance
Distance = 350/50
Distance = 7 meters.
Answer:
A) P1=2 [bar] , W=-12 [kJ]
B) P1=0.8 [bar] , W=-7.3303 [kJ]
C) P1=0.6077 [bar] , W=-6.4091 [kJ]
Explanation:
First, from the problem we know the following information:
V1=0.1 m^3
V2=0.04 m^3
P2=2 bar =200 kPa
The relation PV^n=constant means PV^n is a constant through all the process, so we can derive the initial pressure as:
a) To the case a) the constant n is equal to 0, we can calculate the initial pressure substituting n=0 in the previous expression, so:
The expression to calculate the work is:
If n=0:
Then:
The work is:
b) To the case b) the constant n is equal to 1, we can calculate the initial pressure substituting n=1 in the initial expression, so:
If n=1 then:
To calculate the work:
[/tex]
Substituting:
c) To the case c) the constant n is equal to 1.3, we can calculate the initial pressure substituting n=1.3 in the initial expression, so:
First:
The work:
Substituting:
W=-6.4091 kJ
<u>D: Half</u>
We know that,
F = m.a, where F is the force, m is the object's mass and a is the acceleration.
In the first case, we observed that a1 = F/m.
In the second case, we observed that the mass has been doubled, so a2 = F/2m .
By the ratio of the two cases, we get
a1/a2 = F/m / F/2m
or, a1/a2 = 2
or, a1 = 2.a2
or, a1/2 = a2
Therefore, the acceleration gets <u>half</u> of it's original measurement.