Critical thinking!!!

Physics

1 answer:

insens350 [35]3 years ago

6 0

Answer:

both the cars do same amount of work

Explanation:

okay lemme explain here both will have same displacement and thus the work done will be same for both the cars.. what differs is the power

the power of the 2nd car is double times the power of 1st car.. and hence 2nd will make it to the top of mountain first and first car will take double amount of time

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Determine the mechanical energy of this object: 1-kg ball rolls on the ground at 2 m/s

Fiesta28 [93]

The potential energy would be zero. Only kinetic energy is present in this case. To find out what the answer is we do the equation: mv^2/2 soo...

KE =mv^2/2
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5 0

3 years ago

Kepler’s third law states that for all objects orbiting a given body, the cube of the semimajor axis (A) is proportional to the

GarryVolchara [31]

Explanation:

Kepler’s third law states that for all objects orbiting a given body, the cube of the semimajor axis (A) is proportional to the square of the orbital period (P).

For each of our planets orbiting the Sun, the relationship between the orbital period and semimajor axis can be represented by the equation as:

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One normal afternoon in undisclosed City X, the chocolate factory workers overload the Easter egg machine. A group of angsty tee

musickatia [10]

Answer:

The correct option is;

C. 1,715 m

Explanation:

We are given the information from the group of teen at the City edge

Time of arrival of explosion sound = 5 s after sighting

Time of sighting explosion = 5 s before hearing the boom

Speed of sound in air ≈ 343 m/s

Speed of light = 299,792 km/s

Therefore, distance covered by sound in 5 seconds is given by the following equation;

$Speed = \frac{Distance}{Time}$

$\therefore 343 \ m/s= \frac{Distance}{5 \, s}$

Hence Distance = 343 m/s × 5 s = 1715 m

To check, we compare the time it would take for the light to cover 1715 m

That is $Time = \frac{Distance}{Speed} = \frac{1715}{299,792,000} = 0.00000572 \, s$ which is instantaneous hence the distance can be approximated by the time duration for the speed of sound.