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IceJOKER [234]
2 years ago
11

a ball is tossed straight up in the air to a maximum height of 25 meters before returning to the point that it was thrown, where

it is caught by the one who threw it. When the ball is initially thrown, the thrower imparts an angular velocity of 8 rad/s on the ball, causing it to spin. How many revolutions does the ball make before the person catches the ball?
Physics
1 answer:
boyakko [2]2 years ago
5 0

Answer:

height=25

velocity=8

force of gravity=10

Answer =2000

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Suppose the ski patrol lowers a rescue sled carrying an injured skier, with a combined mass of 97.5 kg, down a 60.0-degree slope
Kitty [74]

a. 1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b.21,835 J work, in joules, is done by the rope on the sled this distance.

c. 23,170 J   the work, in joules done by the gravitational force on the sled d. The net work done on the sled, in joules is 43,670 J.

       

<h3>What is friction work?</h3>

The work done by friction is the force of friction times the distance traveled times the cosine of the angle between the friction force and displacement

a. How much work is done by friction as the sled moves 28m along the hill?

ans. We use the formula:

friction work = -µ.mg.dcosθ

  = -0.100 * 97.5 kg * 9.8 m/s² * 28 m * cos 60

= -1337.3 J

-1337.3 J work, in joules, is done by friction as the sled moved 28 m along the hill.

b. How much work is done by the rope on the sled in this distance?

We use the formula:

Rope work = -m.g.d(sinθ - µcosθ)

rope work = - 97.5 kg * 9.8 m/s² * 28 m (sin 60 – 0.100 * cos 60)

                     = 26,754 (0.816)

                     = 21,835 J

21,835 J work, in joules, is done by the rope on the sled this distance.

c.  What is the work done by the gravitational force on the sled?

By using  the formula:

Gravity work = mgdsinθ

                    = 97.5 kg * 9.8 m/s² * 28 m * sin 60

                    = 23,170 J

23,170 J   the work, in joules done by the gravitational force on the sled .

       

D. What is the total work done?

By adding all the values

work done =  -1337.3 + 21,835 + 23,170

                 = 43,670 J

The net work done on the sled, in joules is 43,670 J.

Learn more about friction work here:

brainly.com/question/14619763

#SPJ1

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2 years ago
Process of changing a liquid into a gas
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Boiling. The temperature at which a liquid begins to boil is called the <span>boiling point.</span>
5 0
3 years ago
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Atmospheric pressure decreases as we go higher up the earth's surface. give reasons
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6 0
3 years ago
What is the value of x? enter your answer in the box. Mm triangle v t k with segment t y such that y is on segment v k, between
Crank

Answer: 98 millimeters

Explanation:

Since angle VTY is congruent to angle VTK, segment TY bisects angle VTK. Since Y is on segment VK, between V and K, we can use the Angle Bisector Theorem, which states that

   (1)

Since x= VK = VY + YK, we need to obtain VY since YK = 68.

VY is obtained by multiplying the denominator YK on both sides of equation (1). So,

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6 0
2 years ago
A rocket sled accelerates from 10 m/s to 40 m/s in 2 seconds. What is the average acceleration of the sled?
Andreas93 [3]

Answer:

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Explanation:

Given parameters:

Initial velocity  = 10m/s

Final velocity  = 40m/s

Time taken  = 2s

Unknown:

Average acceleration  = ?

Solution:

Acceleration is the rate of change of velocity with time;

 Acceleration  = \frac{Final velocity   -  Initial velocity }{time}  

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7 0
2 years ago
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