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IceJOKER [234]
2 years ago
11

a ball is tossed straight up in the air to a maximum height of 25 meters before returning to the point that it was thrown, where

it is caught by the one who threw it. When the ball is initially thrown, the thrower imparts an angular velocity of 8 rad/s on the ball, causing it to spin. How many revolutions does the ball make before the person catches the ball?
Physics
1 answer:
boyakko [2]2 years ago
5 0

Answer:

height=25

velocity=8

force of gravity=10

Answer =2000

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At what speed, as a fraction of c , is a particle's total energy twice its rest energy
WINSTONCH [101]
The rest energy of a particle is
E_0=m_0 c^2
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E=mc^2 =  \frac{m_0 c^2}{ \sqrt{1- \frac{v^2}{c^2} } }
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E=2E_0
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\frac{m_0c^2}{ \sqrt{1- \frac{v^2}{c^2} } }=2m_0 c^2
\frac{1}{ \sqrt{1- \frac{v^2}{c^2} } }=2
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3 0
3 years ago
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Direction of ship: 9.45° West of North

Ship's relative speed: 7.87m/s

Explanation:

A. Direction of ship: since horizontal of the velocity of boat relative to the ground is 0

Vx=0

Therefore, -VsSin∅+VcCos∅40°

Sin∅ = Vc/Vs × Cos 40°

Sin∅ = 1.5/7 ×Cos40°

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∅= Sin-¹ (0.164)

∅= 9.45° W of N

B. Ship's relative speed:

Vy= VsCos∅ + Vcsin40°

= 7Cos9.45° + 1.5sin40°

= 7×0.986 + 1.5×0.642

= 7.865

= 7.87m/s

4 0
3 years ago
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