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4 years ago

LOADS OF POINTS - PLEASE SHOW WORKING AND METHOD USED

Physics

2 answers:

erastova [34]4 years ago

8 0

The formula your looking for is Vf = Vi + A (T)

Vf = Velocity Final
Vi = Velocity Initial
A = Acceleration
T = Time

Our Initial Velocity is 15m/s. That’s our starting point.

Acceleration is -3m/s. It’s negative because we’re slowing down

We know that the cyclist comes to a complete stop, which means the Final Velocity is 0

In order to solve this with the equation. We need three of the four variables. We just don’t know time. So our setup is -

0 = 15-3(T)

Then you solve

NeTakaya4 years ago

4 0

Answer:hi

Explanation:

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A 12000 kg train engine moving at 2.2 m/s hits and locks into 3 boxcars with a total mass of 25000 kg sitting still. If the coll

PilotLPTM [1.2K]

Answer:

V = 0.714m/s

Explanation:

Full solution calculation can be found in the attachment below.

From the principle of conservation of linear momentum, the sum of momentum before collision equals the sum of momentum after collision.

Before collision only the train had momentum. After the collision the train and the boxcars stick together and move as one body. The initial momentum of the train is now shared with the boxcars as they move together as one body. The both move with a common velocity v.

See the attachment below for the solution calculation.

5 0

3 years ago

Read 2 more answers

The automobile has a weight of 2700 lb and is traveling forward at 4 ft>s when it crashes into the wall. If the impact occurs

alex41 [277]

Answer:

$F_b=153918\, lb.ft.s^{-2}$

Explanation:

Given:

mass, $m=2700 \,lb$

time, $t=0.06\,s$

velocity, $v=4\,ft.s^{-1}$

coefficient of kinetic friction between wheels & pavement, $\mu=0.3$

According to first condition,

$F\times \Delta t=m\times v$

$F\times 0.06= 2700\times 4$

$F=180000\,lb.ft.s^{-2}$

According to second condition,

<u>Magnitude of frictional force (which acts opposite to the direction of motion):</u>

$f=\mu.N$

where N is the normal reaction.

$f=0.3\times 2700\times 32.2$

$f=26082 \,lb.ft.s^{-2}$

Now, the impulsive force on the wall if the brakes were applied during the crash:

$F_b= F-f$

$F_b=180000-26082$

$F_b=153918\, lb.ft.s^{-2}$

3 0

3 years ago

A 1500-nF capacitor with circular parallel plates 2.0 cm in diameter is accumulating charge at the rate of 40.0 mC/s at some ins

Delvig [45]

Answer:

$B= 1.14 X 10^{-7} Tesla$

Explanation:

B at point 7.0 cm radially outward is to find out?

Now for field strength in case of parallel plates in given as

$B=\frac{I\mu}{2r\pi}$

$B=\frac{4\pi X 10^{-7} \frac{Tm}{A}X40 X10^{-3} \frac{C}{s}}{2X0.07mX\pi}$

$B= 1.14 X 10^{-7} Tesla$

For the second part as Capacitor is fully charged no more flow of current could take place hence

I= Current =o

so B = 0

6 0

3 years ago

Which two statements describe a situation that would result in a change to landforms on Earth’s surface.

Lilit [14]

Answer:

A. A volcano erupts on a small island.

C. Flooding loosens dirt and rocks along a hillside.

Explanation:

Tectonic activities and mass wasting will greatly lead to a change in land forms on earth's surface.

When a volcano erupts on a small island, a change in landform often results. Also, flooding can lead to changes in land form.

Volcanic eruptions generally adds new materials to the earth surface.
Magma that reaches the surface called lava deposits rock materials unto the surface.
During an extensive period of flooding, materials are carried from one place to another and this greatly sculpts the surface of the earth.

7 0

4 years ago

Why law of floatation is called the special condition of Archimedes principle

Vinil7 [7]

Answer:

Archimedes principle: volume of water displaced by immersed object is equal to volume of water.

so if two object has same volume but different mass

then density determines the flotation of object,if an object has more density than water then it sinks.

I think this is called as special condition of floatation.

7 0

3 years ago