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ruslelena [56]
3 years ago
12

LOADS OF POINTS - PLEASE SHOW WORKING AND METHOD USED

Physics
2 answers:
erastova [34]3 years ago
8 0
The formula your looking for is Vf = Vi + A (T)

Vf = Velocity Final
Vi = Velocity Initial
A = Acceleration
T = Time

Our Initial Velocity is 15m/s. That’s our starting point.

Acceleration is -3m/s. It’s negative because we’re slowing down

We know that the cyclist comes to a complete stop, which means the Final Velocity is 0

In order to solve this with the equation. We need three of the four variables. We just don’t know time. So our setup is -

0 = 15-3(T)

Then you solve

NeTakaya3 years ago
4 0

Answer:hi

Explanation:

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For your answer to this problem, just type in the numerical magnitude of the momentum - no units.
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Answer:

120 kg•m/s.

Explanation:

From the question given above, the following data were obtained:

Case 1

Mass of object = M

Velocity of object = V

Momentum = 15 kg•m/s

Case 2

Mass of object = 2M

Velocity of object = 4V

Momentum = ?

Momentum is defined as follow:

Momentum = mass × velocity

The momentum of object in case 2 can be obtained as follow:

From case 1

Momentum = mass × velocity

15 = M × V

15 = MV ....... (1)

From case 2:

Momentum = mass × velocity

Momentum = 2M × 4V

Momentum = 8MV ....... (2)

Finally , substitute the value of MV in equation 1 into equation 2.

Momentum = 8MV

MV = 15

Momentum = 8 × 15

Momentum = 120 kg•m/s

Therefore, an object with a mass of 2M and 4V would have a momentum of 120 kg•m/s

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