LOADS OF POINTS - PLEASE SHOW WORKING AND METHOD USED
2 answers:
The formula your looking for is Vf = Vi + A (T)
Vf = Velocity Final
Vi = Velocity Initial
A = Acceleration
T = Time
Our Initial Velocity is 15m/s. That’s our starting point.
Acceleration is -3m/s. It’s negative because we’re slowing down
We know that the cyclist comes to a complete stop, which means the Final Velocity is 0
In order to solve this with the equation. We need three of the four variables. We just don’t know time. So our setup is -
0 = 15-3(T)
Then you solve
Vf = Velocity Final
Vi = Velocity Initial
A = Acceleration
T = Time
Our Initial Velocity is 15m/s. That’s our starting point.
Acceleration is -3m/s. It’s negative because we’re slowing down
We know that the cyclist comes to a complete stop, which means the Final Velocity is 0
In order to solve this with the equation. We need three of the four variables. We just don’t know time. So our setup is -
0 = 15-3(T)
Then you solve
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Answer:
Force, F = 77 N
Explanation:
A child in a wagon seem to fall backward when you give the wagon a sharp pull forward. It is due to Newton's third law of motion. The forward pull on wagon is called action force and the backward force is called reaction force. These two forces are equal in magnitude but they acts in opposite direction.
We need to calculate the force is needed to accelerate a sled. It can be calculated using the formula as :
F = m × a
Where
m = mass = 55 kg
a = acceleration = 1.4 m/s²
F = 77 N
So, the force needed to accelerate a sled is 77 N. Hence, this is the required solution.
Answer:
Option B (1.51 m)
Explanation:
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