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ruslelena [56]
3 years ago
12

LOADS OF POINTS - PLEASE SHOW WORKING AND METHOD USED

Physics
2 answers:
erastova [34]3 years ago
8 0
The formula your looking for is Vf = Vi + A (T)

Vf = Velocity Final
Vi = Velocity Initial
A = Acceleration
T = Time

Our Initial Velocity is 15m/s. That’s our starting point.

Acceleration is -3m/s. It’s negative because we’re slowing down

We know that the cyclist comes to a complete stop, which means the Final Velocity is 0

In order to solve this with the equation. We need three of the four variables. We just don’t know time. So our setup is -

0 = 15-3(T)

Then you solve

NeTakaya3 years ago
4 0

Answer:hi

Explanation:

You might be interested in
Se coloca agua en un recipiente de aluminio y se pone a calentar en una estufa que le suministra 230 kj, lo cual hace que la tem
tensa zangetsu [6.8K]

Answer:

32 °C.

Explanation:

Hola.

En este caso, debemos entender que la relación entre el calor y la temperatura viene dada por:

Q=mCp\Delta T

De este modo, dado que estamos estudiando la misma sustancia (agua) con masa constante, la relación calor-temperatura es lineal y directamente proporcional, por tal razón, si se duplica el calor suministrado, la temperatura también será duplicada, de modo que:

\Delta T_{nuevo}=2*16\°C\\\\\Delta T_{nuevo}=32\°C

¡Saludos!

3 0
3 years ago
If a sample emits 2000 counts per second when the detector is 1 meter from the sample, how many counts per second would be obser
Alona [7]

Answer:

<h2><em>6000 counts per second</em></h2>

Explanation:

If a sample emits 2000 counts per second when the detector is 1 meter from the sample, then;

2000 counts per second = 1 meter ... 1

In order to know the number of counts per second that would be observed when the detector is 3 meters from the sample, we will have;

x count per second = 3 meter ... 2

Solving the two expressions simultaneously for x we will have;

2000 counts per second = 1 meter

x counts per second = 3 meter

Cross multiply to get x

2000 * 3 = 1* x

6000 = x

<em></em>

<em>This shows that 6000 counts per second would be observed when the detector is 3 meters from the sample</em>

5 0
3 years ago
A rifle fires a 2.01 10-2-kg pellet straight upward, because the pellet rests on a compressed spring that is released when the t
Zina [86]

Answer:

The value of spring constant is 266.01 \frac{N}{m}

Explanation:

Given:

Mass of pellet m = 2.01 \times 10^{-2} kg

Height difference of pellet rise h_{f} - h_{o} = 6.03 m

Spring compression x = 9.45 \times 10^{-2} m

From energy conservation law,

Spring potential energy is stored into potential energy,

  mg(h_{f} -h_{o})  = \frac{1}{2} kx^{2}

Where k = spring constant, g = 9.8 \frac{m}{s^{2} }

  k = \frac{2mg(h_{f} -h_{o} )}{x^{2} }

  k = \frac{2 \times 9.8 \times 6.03\times 2.01 \times 10^{-2} }{(9.45\times 10^{-2} )^{2} }

  k = 266.01 \frac{N}{m}

Therefore, the value of spring constant is 266.01 \frac{N}{m}

6 0
3 years ago
A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.8 1010 m (inside the orbit
creativ13 [48]

Answer:

Explanation:

From the given information:

Distance d_i = 4.8 \times 10^{10} \ m

Speed of the comet V_i = 9.1 \times 10^{4} \ m/s

At distance d_2 = 6 \times 10^{12} \ m

where;

mass of the sun = 1.98 \times 10^{30}

G = 6.67 \times 10^{-11}

To find the speed V_f:

Using the formula:

E_f = E_i + W \\ \\  where; \  \  W = 0  \ \  \text{since work done by surrounding is zero (0)}

E_f = E_i + 0 \\ \\  K_f + U_f = K_i + U_i  \\ \\ = \dfrac{1}{2}mV_f^2 +  \dfrac{-GMm}{d^2} =  \dfrac{1}{2}mV_i^2+ \dfrac{-GMm}{d_i} \\ \\ V_f = \sqrt{V_i^2 + 2 GM \Big [  \dfrac{1}{d_2}- \dfrac{1}{d_i}\Big ]}

V_f = \sqrt{(9.1 \times 10^{4})^2 + 2 (6.67\times 10^{-11}) *(1.98 * 10^{30} ) \Big [  \dfrac{1}{6*10^{12}}- \dfrac{1}{4.8*10^{10}}\Big ]}

\mathbf{V_f =53.125 \times 10^4 \ m/s}

3 0
3 years ago
A particle moving on a circle has a velocity of 5 m/s and a normal acceleration of 10 m/s^2. What is the radius of the circle?
dybincka [34]

Answer:

Radius of the circle will be 2.5 m

Explanation:

We have given velocity of particle moving in the circle v = 5 m/sec

Acceleration of particle in the circle a=10m/sec^2

We have to find the radius of the circle

We know that acceleration is given by a=\frac{v^2}{r}

So 10=\frac{5^2}{r}

r=\frac{25}{10}=2.5m

So radius of the circle will be 2.5 m

3 0
4 years ago
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