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Ksju [112]
3 years ago
5

A waitress sold 11 ribeye steak dinners and 18 grilled salmon dinners, totaling 592.29 on a particular day. Another day she sold

16 rib eye steak dinners and 6 grilled salmon dinners, totaling 580.56. How much did each type of dinner cost?
Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0

Let the cost of 1 ribeye steak dinner = x

The cost of 1 salmon dinner = y

Then,

11x + 18y = 592.29   (1)

16x + 6y = 580.56   (2)

Multiplying the second equation by 3, we get,

48x + 18y = 1741.68   (3)

(3) - (1) gives

37x = 1149.39

x = 31.06

Substituting the value for x in (1), we get,

11(31.06) + 18y = 592.29

341.66 + 18y = 592.29

18y = 250.63

y = 13.92

Hence, the cost of ribeye steak dinner = 31.06 and the cost of grilled salmon dinner = 13.92.

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yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

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V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

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Step-by-step explanation:

3x+x^2+4

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x^2 +3x+4

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