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oksian1 [2.3K]
3 years ago
14

If the x-intercept (–68, 0), and the y-intercept (0, –34), what is the equation?

Mathematics
2 answers:
andrew-mc [135]3 years ago
7 0

Answer:

Y=-.5x-34

Step-by-step explanation:

this is because you can do y2-y1/x2-x1 to get slope


-34/68


Which equals one half so currently


Y=-1/2x


To get the y intercept we can look at the number when x=0 so it would be -34. So here is the equation


Y=-.5x-34

stealth61 [152]3 years ago
4 0

y = - \frac{1}{2} x - 34

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 68, 0 ) and (x₂, y₂ ) = (0, - 34 )

m = \frac{-34-0}{0+68} = \frac{-34}{68} = - \frac{1}{2}

the y-intercept = (0, - 34 ) ⇒ c = - 34

y= - \frac{1}{2} x - 34


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Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. (a^{x})^{n} = a^{xn}

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). a^{-x} = \frac{1}{a^{x}}, and to help with this question: \frac{a^{-x}b}{1} = \frac{b}{a^{x}}.

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=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}        Negative exponent rule

=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}        Combine the like terms in the numerator with the base "q"

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}        Rearranged for you to see the like terms

=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)+(1/3)}}{p^{(4)}}        Multiplying exponents with same base

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Here is a version in pen if the steps are hard to see.

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