You can solve this by using the system of equations.
Jan - 4.95 = 2H + 3C
Wayne - 5.45 = 3H + 2C
Use elimination.
-3(2H + 3C = 4.95)
2(3H + 2C = 5.45)
Solve. And you'll get:
-6H + (-9C) = -14.85
6H + 4C = 10.9
Cross out -6H and 6H because they cancel out. And you're left with:
-9C = -14.85
4C = 10.9
Add -9C with 4C, and -14.85 with 10.9.
-5C = -3.95
Divide each side with -5.
C = $0.79
Now to figure out what H is, just substitute the C in one of the equations with 0.79.
5.45 = 3H + 2(0.79)
5.45 = 3H + 1.58
-1.58 -1.58
3.87 = 3H
3.87/3 = 3/3(H)
1.29 = H
Finished!
Answer:
Step-by-step explanation:
The key here is knowing that the equation of the line that passes through these points is same
Thus having (6,14) and (0,0), the slope is as follows;
m = y2-y1/x2-x1 = 0-14/0-6 = -14/-6 = 7/3
Now we can use this slope here to get the value of y in the question
All we need to do is tie write the equation of the line for between the points (6,14) and (2,y)
That would be;
7/3 = y-14/1-6
7/3 = y-14/-5
cross multiply;
-35 = 3(y-14)
-35 = -3y + 42
-3y = -35-42
-3y= -77
y = -77/3
y = 77/3
Answer:
m∠N = 32°
NQ = 106°
When finding inscribed angles like ∠N with the intercepted arc, the equation is ∠N=1/2MP. (Inscribed angles are always half the degree of the arc length.) Plug in the corresponding value to get ∠N=1/2(64) to get 32°. When finding the angle of the intercepted arc with inscribed angles like NQ, the equation is NQ=2(∠P). Plug in the corresponding value to get 2(53) to get 106°.
Answer:
-9/5; -1 4/5; -1.8
Step-by-step explanation:
