The amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A
From the question,
We are to calculate, the amount of current flowing in the wire.
From the formula,
Where I is the current
n is the number of charge
Q is the quantity of charge
t is the time
From the given information
n = 8
Q = e = 1.69 × 10⁻¹⁹ C
t = 8 msecs = 8 × 10⁻³ sec
Putting the parameters into the formula, we get
Hence, the amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A
Learn more here: brainly.com/question/22135459
Answer:
Explanation:
Mass of bullet 
Velocity of bullet 
Mass of first block 
Velocity of block 
Mass of second block 
Generally the total momentum before collision is mathematically given as
Generally the total momentum after collision is mathematically given as
Generally the total momentum is mathematically given as
The unit of electric current is the Ampere.
1 Ampere of current means that if you set up your chair and
stare at the electrons flowing past one point in the circuit, you'll
see 1 coulomb of charge passing that point every second.
How will you recognize 1 coulomb of charge ?
Well, every electron carries the same amount of charge, and
we know how much that is. (Read about the Millikan oil-drop
experiment in 1909.) So we know how many electrons it takes
to carry 1 coulomb of charge past the point you're watching.
All you have to do is count the electrons as they zip past.
Every time you count 6,241,509,343,000,000,000 electrons,
you can tick off 1 coulomb of total charge that they're carrying.
If you reach that count every second, you know the current
passing that point is 1 Ampere.
Answer:
Fgparallel = 170N
Explanation:
Acting down the incline would be the paralell force. The Force of gravity on an incline for the parallel portion is mgsinθ.
Fg parallel = mgsinθ
mg is 289.9, as that is the weight. θ is 35.9
Fgpar = 289.9sin35.9
Fgparallel = 170N
