Answer:
a)The electric Field will be zero at the point between the sheets
b)
c)
Explanation:
Let
be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field so the Electric Flux due to it is zero.
Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

The Field will be away from the sheet and perpendicular to it.
a) The Electric Field between them

b)The Electric Field to the right of the sheets

c)The Electric Field to the left of the sheets

Explanation:
It took
for the sound to reach the 1st wall and at the same time time, the same sound took
to reach the 2nd wall. Assuming that the sound travels at 343 m/s, then let
be the distance of the person to the 1st wall and
be the distance to the 2nd wall. So the distance between the walls X is


Answer: = . /
Explanation:
The acceleration is
= − 0
In our case, the initial velocity has minus sign.
Thus,
=
− (−0)
=
+ 0
Substituting
0 =
2
(
+
0
) −
=
2
+
0
2
−
Thus,
0
2
=
2
−
So,
0 = −
= 8.62 −
12.9
8.25 = 7.06 m/s
Answer: = . /
Explanation:
(a) We know that the acceleration of the car is given by :
a = change in speed / time taken
If the speed of the car is constant in a straight line, the acceleration of the car is zero because there is no change in the speed of the car.
(b) For the driver steer a car traveling at constant speed so that the magnitude of the acceleration remains constant, the driver should drive the car in the circular path. This is because, in circular path the speed of an object remains the same while its velocity changes.
Explanation:
Mass and energy are closely related. Due to mass–energy equivalence, any object that has mass when stationary (called rest mass) also has an equivalent amount of energy whose form is called rest energy, and any additional energy (of any form) acquired by the object above that rest energy will increase the object's total mass just as it increases its total energy. For example, after heating an object, its increase in energy could be measured as a small increase in mass, with a sensitive enough scale.