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Deffense [45]
3 years ago
10

Earth's orbit around the sun is not perfectly circular. The nearest point of its orbit is 1.471E8 kilometers. The mass of the su

n is 1.989E30 kilograms. The mass of the earth is 5.97E24 kilograms. The universal gravitational constant is 6.6738E-11 N(m/kg)2. (a) What is the force exerted by the sun on the earth they are closest together? (b) What is the corresponding force of the earth on the sun?
Physics
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

a) -3.66233E22 N

b) 3.66233E22 N

Explanation:

Closest distance between Earth and Sun = 1.471E8 kilometers = r

Mass of Earth = 5.97E24 kilograms = m

Mass of the sun = 1.989E30 kilograms = M

a) Universal gravitational constant = 6.6738E-11 N(m/kg)2

F_{Mm}=-G\frac{Mm}{r^2}\\\Rightarrow F=-6.6738E-11 N \frac{5.97E24\times 1.989E30}{(1.471E11)^2}\\\Rightarrow F=-3.66233E22\ N

Force exerted by the sun on the earth they are closest together is -3.66233E22 N

b) The magnitude of the force that the earth will exert on the sun will be same but the direction will be different represented by the change of the sign

F_{mM}=-F_{Mm}\\\Rightarrow F_{mM}=-(-3.66233E22\ N)\\\Rightarrow F_{mM}=3.66233E22\ N

Force exerted by the earth on the sun when they are closest together is 3.66233E22 N.

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Two large, parallel, nonconducting sheets of positive charge face each other. What is at points (a) to the left of the sheets, (
alexira [117]

Answer:

a)The electric Field will be zero at the point between the sheets

b)E_1=\dfrac{\sigma}{\epsilon_0}

c)E_2=\dfrac{\sigma}{\epsilon_0}

Explanation:

Let \sigma be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field  so the Electric Flux due to it is zero.

Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

E\times 2A=\dfrac{\sigma A}{\epsilon_0}\\E=\dfrac{\sigma}{2\epsilon_0}

The Field will be away from the sheet and perpendicular to it.

a) The Electric Field between them

E_1=\dfrac{\sigma}{2\epsilon_0}-\dfrac{\sigma}{2\epsilon_0}\\=0

b)The Electric Field to the right of the sheets

E_1=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

c)The Electric Field to the left of the sheets

E_2=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

3 0
3 years ago
a student standing between two walls shouts once.he hears the first echo after 3 seconds and the next after 5 seconds. calculate
Karolina [17]

Explanation:

It took t_1 =1.5\:\text{s} for the sound to reach the 1st wall and at the same time time, the same sound took t_2 = 2.5\:\text{s} to reach the 2nd wall. Assuming that the sound travels at 343 m/s, then let x_1 be the distance of the person to the 1st wall and x_2 be the distance to the 2nd wall. So the distance between the walls X is

X = x_1 + x_2 = v_st_1 + v_st_2 = v_s(t_1 + t_2)

\:\:\:\:\:= (343\:\text{m/s})(4.0\:\text{s}) = 1372\:\text{m}

6 0
3 years ago
a car is rolling backward when it hits the gas. after 8.25 s it is moving forward at 8.62m/s, and is 12.9m to the right of its s
MAXImum [283]

Answer: = . /

Explanation:

The acceleration is

=   − 0

In our case, the initial velocity has minus sign.

Thus,

= − (−0) = + 0

Substituting

0 = 2 ( + 0 ) − = 2 + 0 2 −

Thus,

0 2 = 2 −

So,

0 = − = 8.62 − 12.9

8.25 = 7.06 m/s

Answer: = . /

7 0
4 years ago
Read 2 more answers
(a) How can a driver steer a car traveling at constant speed so that the acceleration is zero? (Assume that the road is level. S
PilotLPTM [1.2K]

Explanation:

(a) We know that the acceleration of the car is given by :

a = change in speed / time taken

If the speed of the car is constant in a straight line, the acceleration of the car is zero because there is no change in the speed of the car.

(b) For the driver steer a car traveling at constant speed so that the magnitude of the acceleration remains constant, the driver should drive the car in the circular path. This is because, in circular path the speed of an object remains the same while its velocity changes.

8 0
3 years ago
When you release the mass, what do you observe about the energy?
anygoal [31]

Explanation:

Mass and energy are closely related. Due to mass–energy equivalence, any object that has mass when stationary (called rest mass) also has an equivalent amount of energy whose form is called rest energy, and any additional energy (of any form) acquired by the object above that rest energy will increase the object's total mass just as it increases its total energy. For example, after heating an object, its increase in energy could be measured as a small increase in mass, with a sensitive enough scale.

3 0
3 years ago
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