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Deffense [45]
3 years ago
10

Earth's orbit around the sun is not perfectly circular. The nearest point of its orbit is 1.471E8 kilometers. The mass of the su

n is 1.989E30 kilograms. The mass of the earth is 5.97E24 kilograms. The universal gravitational constant is 6.6738E-11 N(m/kg)2. (a) What is the force exerted by the sun on the earth they are closest together? (b) What is the corresponding force of the earth on the sun?
Physics
1 answer:
BARSIC [14]3 years ago
7 0

Answer:

a) -3.66233E22 N

b) 3.66233E22 N

Explanation:

Closest distance between Earth and Sun = 1.471E8 kilometers = r

Mass of Earth = 5.97E24 kilograms = m

Mass of the sun = 1.989E30 kilograms = M

a) Universal gravitational constant = 6.6738E-11 N(m/kg)2

F_{Mm}=-G\frac{Mm}{r^2}\\\Rightarrow F=-6.6738E-11 N \frac{5.97E24\times 1.989E30}{(1.471E11)^2}\\\Rightarrow F=-3.66233E22\ N

Force exerted by the sun on the earth they are closest together is -3.66233E22 N

b) The magnitude of the force that the earth will exert on the sun will be same but the direction will be different represented by the change of the sign

F_{mM}=-F_{Mm}\\\Rightarrow F_{mM}=-(-3.66233E22\ N)\\\Rightarrow F_{mM}=3.66233E22\ N

Force exerted by the earth on the sun when they are closest together is 3.66233E22 N.

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2 years ago
Consider a steel guitar string of initial length L=1.00 meter and cross-sectional area A=0.500 square millimeters. The Young's m
Reil [10]

Answer:

\Delta l=0.015m

Explanation:

We have given initial length of the steel guitar l = 1 m

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So stress =\frac{force}{area}=\frac{1500}{0.5\times 10^{-6}}=3000\times 10^{-6}=3\times 10^{9}Pa

We know that young's modulus =\frac{stress}{strain}

So 2\times 10^{11}=\frac{3\times 10^{9}}{strain}

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3 years ago
Read 2 more answers
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