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tigry1 [53]
3 years ago
14

You place a box weighing 289.9 N on an inclined plane that makes a 35.9 degree angle with the horizontal. Compute the component

of the gravitational force acting down the inclined plane. Answer in units of N
Physics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:

Fgparallel =  170N

Explanation:

Acting down the incline would be the paralell force. The Force of gravity on an incline for the parallel portion is mgsinθ.

Fg parallel = mgsinθ

mg is 289.9, as that is the weight. θ is 35.9

Fgpar = 289.9sin35.9

Fgparallel =  170N

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