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tigry1 [53]
3 years ago
14

You place a box weighing 289.9 N on an inclined plane that makes a 35.9 degree angle with the horizontal. Compute the component

of the gravitational force acting down the inclined plane. Answer in units of N
Physics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer:

Fgparallel =  170N

Explanation:

Acting down the incline would be the paralell force. The Force of gravity on an incline for the parallel portion is mgsinθ.

Fg parallel = mgsinθ

mg is 289.9, as that is the weight. θ is 35.9

Fgpar = 289.9sin35.9

Fgparallel =  170N

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Answer:

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6 0
3 years ago
A rocket initially at rest accelerates at a rate of 99. 0 meters/second2. Calculate the distance covered by the rocket if it att
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<h3>What is acceleration?</h3>

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From kinamatic equation:

D = v_{t} +\dfrac 12at^2

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t - time =  4. 50 s

Put the values in the formula,

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Learn more about Acceleration :

brainly.com/question/2697545

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2 years ago
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6 0
3 years ago
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