Question

Calculate amount of current flowing in wire if number of charge is 8 and e = 1.69 x10^-19 , t= 8millsec

Answer 1

The amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A

From the question,

We are to calculate, the amount of current flowing in the wire.

From the formula,

$I =\frac{nQ}{t}$

Where I is the current

n is the number of charge

Q is the quantity of charge

t is the time

From the given information

n = 8

Q = e = 1.69 × 10⁻¹⁹ C

t = 8 msecs = 8 × 10⁻³ sec

Putting the parameters into the formula, we get

$I = \frac{8 \times 1.69 \times 10^{-19} }{8\times 10^{-3} }$

$I = 1.69 \times 10^{-16} \ A$

Hence, the amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A

Learn more here: brainly.com/question/22135459