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Rasek [7]
3 years ago
6

Tickets for a raffle cost $13. There were 810 tickets sold. One ticket will be randomly selected as the winner, and that person

wins $1100 and also the person is given back the cost of the ticket. For someone who buys a ticket, what is the Expected Value (the mean of the distribution)?
Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0

Answer:

$ -11.61

Step-by-step explanation:

The expected value in this case would be the subtraction between the probability that the draw will win for its value (the prize + value of the ticket) and the value of the ticket for the probability of not winning the draw, thus:

(1/810) * (1100 + 13) - (809/810) * (13)

1,374 -12,984 = -11.61

which means that the expected value is $ -11.61

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Ad libitum [116K]

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1372 inches

Step-by-step explanation:

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196*7=1372

8 0
3 years ago
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Use truth tables to show that the following statements are logically equivalent. ∼ P ⇔ Q = (P ⇒∼ Q)∧(∼ Q ⇒ P)
Alina [70]

Answer:  The given logical equivalence is proved below.

Step-by-step explanation:  We are given to use truth tables to show the following logical equivalence :

∼ P ⇔ Q ≡ (P ⇒∼ Q)∧(∼ Q ⇒ P)

We know that

two compound propositions are said to be logically equivalent if they have same corresponding truth values in the truth table.

The truth table is as follows :

P     Q     ∼ P     ∼Q   ∼ P⇔ Q    P ⇒∼ Q    ∼ Q ⇒ P     (P ⇒∼ Q)∧(∼ Q ⇒ P)

T     T         F        F             F            F                   T                       F

T     F         F        T             T             T                   T                       T

F     T         T        F             T            T                   T                       T

F     F         T        T             F            T                   F                       F

Since the corresponding truth vales for ∼ P ⇔ Q and (P ⇒∼ Q)∧(∼ Q ⇒ P) are same, so the given propositions are logically equivalent.

Thus, ∼ P ⇔ Q ≡ (P ⇒∼ Q)∧(∼ Q ⇒ P).

8 0
3 years ago
Andrew solved the following inequality, and his work is shown below:
Nataly_w [17]
It’s B. When dividing by -2, he did not change the direction of the sign
3 0
3 years ago
What is the midpoint between the points (1, 4) and (-3, 2)?
emmasim [6.3K]
\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 1}}\quad ,&{{ 4}})\quad 
%  (c,d)
&({{ -3}}\quad ,&{{ 2}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
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6 0
3 years ago
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Tasya [4]
So there are a totally of 52 cards right?(not counting jokers because jokers are not in official cards)
And there are 4 aces right?
So there are 52 outcomes and 4 of them are aces.
So when we write probabilities we write it in fraction form where the total number of outcomes is the denominator and the ones you want to get are the numerator OK?
So the total number is outcomes is 52 and becomes the denominator and 4 the number of aces become the numerator.
So 4/52 right?
And we now have to simplify it right?
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In this case 4 because there isn’t other numbers that are factors and greater than 4.
So 4 divided by 4/52 is 1/13 right?
4 goes into 4 1 time and 13 times into 52.
So your answer is 1/13
3 0
3 years ago
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