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olga nikolaevna [1]
3 years ago
10

* WILL MARK BRAINLIEST PLEASE HELP ! *

Mathematics
2 answers:
puteri [66]3 years ago
5 0
When finding terms, you must substitute in the term you need to find for n. So, to find the second term, you would do a(2)=5+(2-1)(7), and after solving the answer should be 13. To find the fifth term, it’s a(5)=5+(5-1)(7). After solving that would equal 33. Try the next one to see if you understand it, it’s mostly substituting numbers for n and solving! I hope I helped :)
yuradex [85]3 years ago
4 0
Answers:
The second term is 2
The fifth term is 23
The ninth term is 51

-----------------------------------------------------------

Explanation:

To find the second term, replace every n with 2 and use PEMDAS to simplify
a(n) = -5+(n-1)(7)
a(2) = -5+(2-1)(7)
a(2) = -5+(1)(7)
a(2) = -5+7
a(2) = 2
The second term is 2

Similarly, plug in n = 5 to get the fifth term
a(n) = -5+(n-1)(7)
a(5) = -5+(5-1)(7)
a(5) = -5+(4)(7)
a(5) = -5+28
a(5) = 23
The fifth term is 23

Finally, replace every n with 9 to find the ninth term
a(n) = -5+(n-1)(7)
a(9) = -5+(9-1)(7)
a(9) = -5+(8)(7)
a(9) = -5+56
a(9) = 51
The ninth term is 51

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Q4. An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculat
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Answer:

I) \dfrac{1}{8}  (ii) \dfrac{53}{64}   (iii) \dfrac{15}{64}   (iv) \dfrac{5}{8}   (v)\dfrac{21}{32}

Step-by-step explanation:

The sample space for an 8-sided fair die rolled twice is:

[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]\\

(a) Possibility diagram of the product of the two numbers appearing on the die in each throw

1, 2, 3, 4, 5, 6,7,8\\2, 4, 6, 8, 10, 12,14,16\\3,6,9,12,15,18,21,24\\4,8,12,16,20,24,28,32\\5,10,15,20,25,30,35,40\\6.12,18,24,30,36,42,48\\7,14,21,28,35,42,49,56\\8,16,24,32,40,48,56,64

(b)

I) A prime number  

P$(Product is a prime number)=\dfrac{8}{64}= \dfrac{1}{8}

ii) Not a perfect square  

Number of Perfect Squares =11

P(Product is Not a perfect square)  =\dfrac{64-11}{64}= \dfrac{53}{64}

iii) A multiple of 5

Number of Multiples of 5=15

P$(A multiple of 5)=\dfrac{15}{64}

iv) Less than or equal to 21

Product less than or equal to 21=40

P$(Less than or equal to 21)=\dfrac{40}{64}=\dfrac{5}{8}

v) Divisible by 4 or 6

Products Divisible by 4 or 6= 42

P$(Divisible by 4 or 6)=\dfrac{42}{64}=\dfrac{21}{32}

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