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3 years ago

Please help, A B C or D , please help

Mathematics

1 answer:

Readme [11.4K]3 years ago

6 0

Answer:d

Step-by-step explanation:

Huh. For example there is d

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The volume of a cylinder is 252π252π cm3 and its height is 7 cm.

kirill [66]

V = (pi) * r^2 * h
h = 7
V = 252(pi)

252(pi) = r^2 * 7
252(pi) / 7 = r^2
36(pi) = r^2
sqrt 36(pi) = r
6 = r <==== radius is 6 cm

8 0

3 years ago

What is nine thousand one hundred forty five divided by 3

Galina-37 [17]

Answer:

3,315 is the answer

Step-by-step explanation:

1) Just divide

9945 ÷ 3 = 3,315

Not hard

But here my answer!

3 0

3 years ago

Read 2 more answers

Use f(x) = 1 2 x and f -1(x) = 2x to solve the problems.

AVprozaik [17]

Answer:

The answer to your question is below

Step-by-step explanation:

Functions

f(x) = 12x f⁻¹(x) = 2x

a) f⁻¹(-2) = 2(-2)

f⁻¹(-2) = -4

b) f(-4) = 12x

f(-4) = 12(-4)

f(-4) = -48

c) f(f⁻¹(-2)) =

f(f⁻¹(x)) = 12(2x) = 24x

f(f⁻¹(-2)) = 24(-2) = -48

I think your functions are wrong they must be f(x) = 1/2x f⁻¹(x) = 2x

a) f⁻¹(-2) = 2(-2)

= -4

b) f(-4) = 1/2(-4)

= -2

c) f(f⁻¹(x)) = 1/2(2x)

= x

f(f⁻¹(-2)) = -2

4 0

3 years ago

An equation of the horizontal line that passes through the point (-2,5)

Greeley [361]

Y=5 it's a horizontal lines so b in y=mx+b would have to be 5 and since it's horizonal, it doesn't have a slope so it's just y=5

8 0

4 years ago

1. Write the standard form of the line that passes through the given points. (7, -3) and (4, -8)

Sveta_85 [38]

Answer:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$ .

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e., $m=\dfrac{y_2-y_1}{x_2-x_1}$ .

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$ .

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$ .

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$ .

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$ .

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$ .

5 0

3 years ago