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Zina [86]
3 years ago
11

The letters in the given list are written on tiles, one letter per tile. A, B, C, F, G, I, K, L, O, P, Q, T, V, W, X, Z The 16 t

iles are placed in a bag and one is drawn randomly. Determine the probability of specific events using this situation.
Mathematics
1 answer:
Butoxors [25]3 years ago
6 0

Answer:

(a) \frac{1}{16}

(b)\frac{1}{8}

(c)\frac{3}{16}

(d)\frac{15}{16}

Step-by-step explanation:

The letters in each tile are:

A, B, C, F, G, I, K, L, O, P, Q, T, V, W, X, Z

Total Number of tiles n(S)=16

(a)The probability of drawing any one of the letters

The Probability of drawing any one of the letters =\dfrac{1}{n(S)}=\dfrac{1}{16}

(b)The probability of drawing either an "F" or "P" tile

P(Either an F or a P Tile) = P(drawing an F Tile )+P(drawing a P Tile)

=\dfrac{1}{16}+\dfrac{1}{16}\\=\dfrac{2}{16}\\=\dfrac{1}{8}

(c)The probability of drawing a vowel

The Vowel Tiles are: A,I,O

Number of Vowels =3

\text{P(Drawing a vowel)}=\dfrac{3}{16}

(d)The probability of not drawing a "Q" tile

\text{P(Drawing a Q tile)}=\dfrac{1}{16}\\Therefore:\\\text{P(Not Drawing a Q tile)}=P(Q^c)=1-\dfrac{1}{16}\\=\dfrac{15}{16}

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We have that  the fourth term of an arithmetic sequence is

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Option C

From the question we are told

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