I think the answer is proton
The magnitude of the magnetic field on the axis of the ring 5 cm from its center is 143 pT.
The radius of the nonconducting ring is R = 10 cm.
The ring is uniformly charged q = 10 μC.
The angular speed of the ring, ω = 20 rad/s
The ring is x = 5 cm from the center of the ring.
Now,
R = 10 cm = 0.1 m
q = 10.0 μC = 10 × 10⁻⁶ C
x = 5 cm = 0.05 m
The magnetic field on the axis of a current loop is given as:
B = [ μ₀ IR² ] / [4π(x² + R²)^{3/2} ]
Now, I = q / [2π/ω]
So, the magnitude of the magnetic field which is directed away from the center is:
B = [ μ₀ ωqR² ] / [4π(x² + R²)^{3/2} ]
B = [ μ₀ (200) (10 × 10⁻⁶) (0.1)² ] / [4π((0.05)² + (0.1)²)^{3/2} ]
B = 1.43 × 10⁻¹⁰ T
B = 143 pT
Learn more about the magnetic field here:
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Answer:
Explanation:
The earth makes in 365 day 1 revolution
The earth makes in 1 day 1 / 365 revolutions
1 / 365 revolution per day
n = 1 / 365 per day .
n is called frequency of revolutions .
Angular velocity = 2π n
= 2 π x 1 / 365
= .0172 radian / day
It would be the electromagnet because that is how it spins
Answer:
14
Explanation:
The total no of protons and neutrons in an atomic nucleus is called mass number, nucleon number or atomic mass number. It is denoted by A.
In this problem, we need to find the nucleon number of carbon-14 i.e. mass number of carbon -14. 14 with carbon shows its mass number.
Hence, the nucleon no of carbon-14 is 14.
