(a) The period of the oscillation is 0.8 s.
(b) The frequency of the oscillation is 1.25 Hz.
(c) The angular frequency of the oscillation is 7.885 rad/s.
(d) The amplitude of the oscillation is 3 cm.
(e) The force constant of the spring is 148.1 N/m.
The given parameters:
- <em>Mass of the ball, m = 2.4 kg</em>
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From the given graph, we can determine the missing parameters.
The amplitude of the wave is the maximum displacement, A = 3 cm
The period of the oscillation is the time taken to make one complete cycle.
T = 0.8 s
The frequency of the oscillation is calculated as follows;

The angular frequency of the oscillation is calculated as follows;

The force constant of the spring is calculated as follows;

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The correct answer is - C. Crustal plates, crustal plates.
The movement of the crustal plates of the Earth is the reason why the geologic processes are occurring on our planet. With their movement, the crustal plates manage to create lot of pressure, open up gaps for the magma from the mantle, as well as make adjustments deeper into the ground.
Because of the adjustments deep into the ground, or rather the crust, lot of force is released, manifested as strong and very quick vibrations, better known as earthquakes.
The gaps that are opening between the plates let the magma reach the surface, thus enabling the volcanic activities on the planet.
The pressure from the plates' collision makes the land lift up slowly, and over time a mountain range starts to form because of the continuous lifting up of the area.
Answer:
F = 1.63 x 10⁻⁹ N
Explanation:
Complete question is as follows:
The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers. Find the magnitude of Gravitational Force?
Answer:
The gravitational force is given by Newton's Gravitational Law as follows:
F = Gm₁m₂/r²
where,
F = Gravitational Force = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = m₂ = mass of each ball = 7 kg
r = distance between balls = 2 m
Therefore,
F = (6.67 x 10⁻¹¹ N.m²/kg²)(7 kg)(7 kg)/(2 m)²
<u>F = 1.63 x 10⁻⁹ N</u>
The magnitude of the gravitational force exerted by ball A on ball B is equal to 36.31 × 10⁻¹¹ N.
<h3>What is gravitational force?</h3>
Newton’s law of gravitation can be defined as every particle of matter in the universe attracting every other particle with mass with a certain force. The magnitude of gravitational force has a direct relationship with their masses.
Therefore, the gravitational force between two bodies can be written as:

Where G denotes the universal gravitational constant.
Given, the mass of the Ball A = Ball B = 7 Kg
The separation between the two balls, r = 3 m
The magnitude of the gravitational force applied by ball A on ball B can be determined as:

F = 36.31 × 10⁻¹¹ N
Therefore, the gravitational force is equal to 36.31 × 10⁻¹¹ N.
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