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Veseljchak [2.6K]
3 years ago
5

What is the oxidation state of an individual phosphorus atom in P O 3 3−?

Chemistry
1 answer:
Tju [1.3M]3 years ago
4 0
-3 - 3(-2) = +3
___________________
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Which of the following would have the largest atomic radius?
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Potassium forms ions with a charge of +1 (K+). Iodine forms ions with a charge of -1. Selenium forms ions with a charge of -2 (S
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It is given that the charge on potassium is +1 i.e. Potassium is a cation, K⁺

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3 0
4 years ago
SO42- 2NO2 H2OH2SO3 2NO3- In the above redox reaction, using oxidation numbers to identify the element oxidized, the element red
nignag [31]

Answer :  In the redox reaction,

Nitrogen element is oxidized and sulfur element is reduced.

NO_2 act as reducing agent and SO_4^{2-} act as an oxidizing agent.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

SO_4^{2-}+2NO_2+H_2O\rightarrow H_2SO_3+2NO_3^-

This reaction is a redox reaction in which nitrogen shows oxidation reaction because the oxidation state of 'N' changes from (+4) to (+5) and sulfur shows reduction reaction because the oxidation state of 'S' changes from (+6) to (+4).

In the redox reaction NO_2 act as reducing agent and SO_4^{2-} act as an oxidizing agent.

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