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larisa [96]
3 years ago
10

Diagram how an acid can be nuetralized

Chemistry
1 answer:
KengaRu [80]3 years ago
7 0

To neutralize acids, a weak base is used. Bases have a bitter or astringent taste and a pH greater than 7. Common bases are sodium hydroxide, potassium hydroxide and ammonium hydroxide. Bases are neutralized by using a weak acid.

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An equilibrium mixture contains 0.750 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the
sasho [114]

1.302  moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}

While the equilibrium constant is based on partial pressure

\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}

The value of Kp and Kc can be linked to the formula '

\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}

R = gas constant = 0.0821 L.atm / mol.K

=n = number of product coefficients-number of reactant coefficients

An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O

  • We determine Kc (constant concentration)

\displaystyle Kc=\frac{0.75.0.75}{0.2.0.2}\\\\Kc=14.1

  • the amount of carbon monoxide to 0.300 mol

Reaction :

                CO +H₂O ⇔ CO₂ + H₂

initially      0.2   0.2       0.75+x  0.75

reaction    0.1    0.1        0.1         0.1

product     0.3   0.3       0.65+x    0.65

\displaystyle Kc=\frac{(0.650+x)(0.65)}{0.3.0.3}\\\\14.1(0.09)=0.4225+0.65x\\\\1.269-0.4225=0.65x\\\\0.8465=0.65x\\\\x=1.302

<h3>Learn more</h3>

an equilibrium constant brainly.com/question/9173805

brainly.com/question/1109930

Calculate the value of the equilibrium constant, Kc

brainly.com/question/3612827

Concentration of hi at equilibrium

brainly.com/question/8962129

Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient

3 0
4 years ago
Read 2 more answers
3. Give three examples of a pure substances
Nadya [2.5K]

Answer:

There will be weight, there will be volume, there will be height

Explanation:

5 0
3 years ago
Read 2 more answers
Nitrobenzene contains 5 hydrogen atoms 6 carbon atoms 2 oxygen atoms and 1 nitrogen atom. what is the chemical formula for nitro
tamaranim1 [39]
To develop the chemical formula of a substance or compound in this regard, one only needs to write the chemical symbol for each of the element present and write as subscript to each symbol the number of atoms of that element. For nitrobenzene, as described above, the chemical formula should be,
                      C₆H₅O₂N
3 0
3 years ago
Round the following answer correctly. 5.40m x 3.21m x 1.871m = 32.431914 m^3
Klio2033 [76]
The answer is 32.43 because when you round the number next to the hunthers place (witch in this problem would be the 1) has to be 5 or hight to raise the number to the left of it and if it is lower you just take the two number and that is your answer.
5 0
3 years ago
A plate and frame filter press with 12 frames is used to filter slurry at constant pressure. Total filtration area is 65 ft2 and
Vladimir [108]

Answer:

t_2 = 14.4 min

Explanation:

Given data:

Number of frame is 12+ 8 = 20

Total filtrate is 360 lb

we know

For 1 plate area = \frac{65}{12} ft^2

Then for 20 are PLATE = 20\tmes \frac{65}{12} ft^2 = 108.33 ft^2

filtrate equation is given as

t\frac{\mu_s\times(\alpha v) V^2}{A^2(-\Delta P)}

In the above equation only t and A is variable , all other terms are constant

Therefore we have

\frac{t_2}{t_1}= \frac{A_1}{A_2} = [\frac{65}{105.33}]^2 = 0.36

t_2 = 0.36\times 40 = 14.4 min

t_2 = 14.4 min

5 0
4 years ago
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