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1 year ago

Describe two carbon sequestering methods that could reduce the impact of deforestation

1 answer:

6 0

The two carbon-sequestering methods that could reduce the impact of deforestation are afforestation and agriculture.

Carbon sequestering

It is a process of capturing and storing the carbon dioxide gas of an atmosphere on a large scale.
This is done to prevent adverse global climatic conditions
The methods which can reduce the impact of deforestation are afforestation, wetlands, fertilizing ocean surfaces, agriculture, etc.

Afforestation

Planting trees in the nonforest region or planting trees in the deforested region.
By this more and more carbon dioxide gas will be absorbed by the tress from the atmosphere via photosynthesis and that will get involve in the carbon cycle.
Help in re-establishing an ecosystem in the region and prevent soil erosion.

Agriculture

Growing and planting crops which maintain carbon level of the soil, And along with absorbs carbon dioxide gas from the atmosphere.
Will increase the concentration of oxygen gas in the atmosphere leading to prevent air pollution.

Learn more about carbon sequestering here:

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Given below is the balanced equation for the combustion of decane. 2C10H22 (l) + 31O2 (g) --> 20CO2 (g) + 22H2O (g) What is t

Aleks [24]

Answer: The ratio of carbon dioxide molecules to oxygen molecules is 20 :31

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced combustion reaction is,:

$2C_{10}H_{22}(l)+31O_2(g)\rightarrow 20CO_2(g)+22H_2O(g)$

Thus the ratio of carbon dioxide molecules to oxygen molecules is 20 : 31

3 0

2 years ago

Which produces the most energy? A. passing 5 kg of water through a hydroelectric power plant. B. fissioning 5 kg of uranium. C.

blagie [28]

Answer:

D. fusing 5 kg of hydrogen.

Explanation:

8 0

2 years ago

The distance between the centers of the two oxygen atoms in an oxygen molecule is 1.21 x 10-8 cm. What is this distance in inche

Sergio [31]

Answer:

$d=4.75\times 10^{-9}\ \text{inches}$

Explanation:

Given that,

The distance between the centers of the two oxygen atoms in an oxygen molecule is $1.21\times 10^{-8}\ cm$ .

We need to convert this distance in inches.

We know that,

1 cm = 0.393 inches

We can solve it as follows :

$1.21\times 10^{-8}\ cm=0.393\times 1.21\times 10^{-8}\\\\=4.75\times 10^{-9}\ \text{inches}$

So, the distance between the centers of the two oxygen atoms is $4.75\times 10^{-9}\ \text{inches}$ .

5 0

2 years ago

In the name, iron(III) oxide, the (III) represents

miss Akunina [59]

Answer:

Explanation:

the number o iron atoms

7 0

2 years ago

what is the mass of water vapor produced when 3.2 liters reacts with 8.7 liters of oxygen gas at STP?

uranmaximum [27]

Answer:

2.57g

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

2H2 + O2 —> 2H2O

Next let us determine the limiting reactant. This is achieved as follows:

From the equation,

2L H2 required 1L of O2.

Therefore, 3.2L of H will require = 3.2/2 = 1.6L of O2

From the calculation above, O2 is excess because the volume of O2 given from the question is far greater than the volume of O2 obtained from our calculation. Therefore, H2 is the limiting reactant.

Now let us covert 3.2L of H2 to mole. This is illustrated below:

1mole of a gas occupy 22.4L at stp

Therefore, Xmol of H2 will occupy 3.2L i.e

Xmol of H2 = 3.2/22.4 = 0.143mol

From the equation,

2moles of H2 produced 2moles of H2O.

Therefore, 0.143mol of H2 will also produce 0.143moles of H2O.

Now, we can obtain the mass of the water vapour produced by convert 0.143mol of H2O to gram. This is illustrated below:

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Number of mole of H2O = 0.143mol

Mass of H2O =?

Mass = mole x Molar Mass

Mass of H2O = 0.143 x 18 = 2.57g

The mass of water vapour produce is 2.57g

8 0

2 years ago