Help. The answer to question 1 I didn't mean to click so please answer that as well.
1 answer:
We have that energy=specific heat * change in temperature * mass. Thus, we have the final temperature (22) minus the initial temperature (55) to equal -33 as our change in temperature. Our specific heat is in J/g*C, so we're good with that because g stands for grams and the aluminium is measured in grams. As there are 10 grams of aluminum, we have
as our final temperature
An exothermic reaction would release energy and would therefore lose heat itself, while an endothermic reaction would absorb energy and gain heat. Therefore, losing heat would be an exothermic reaction
Feel free to ask further questions!
An exothermic reaction would release energy and would therefore lose heat itself, while an endothermic reaction would absorb energy and gain heat. Therefore, losing heat would be an exothermic reaction
Feel free to ask further questions!
You might be interested in
Answer : The sketch of two amino acids side by side are shown below.
Explanation :
Amino acid : Amino acid are the acid that contains two functional groups which are carboxylic group, and ammine group,
.
When the two or more that two amino acids join together with the help of peptide bond, they produces polypeptide chain or protein.
The bond present between the two amino acid is called a peptide bond.
The peptide bond is a chemical bond that is formed between the two molecules when the nitrogen of one amino acid react with the carbon of another amino acid by releasing a water molecule.
Hence, the sketch of two amino acids side by side are shown below.
Answer: The correct answer is: " 0.54 g " .
__________________________________________
Explanation:
Note that "hydrogen gas" is:
H₂ (g) ; that is: a "diatomic element" (diatomic gas) ;
_________________________________________
The molecular weight of "H" is: 1.00794 g ;
(From the Periodic Table of Elements).
So, the molecular weight of: H₂ (g) is:
" 1.00794 g * 2 = 2.01588 g ; {use calculator) ;
_________________________________________
Note the conversion for a gas at STP:
______
1 mol of a gas = 22.4 L gas;
___
i.e. " 1 mol / 22.4 L " ;
____
So: " 5.7 L H₂ (g)
The "L" ("literes" cancel out to "1" ; since "L/L = 1 ;
The "mol" (moles) cancel out to "1" ; since "mol/mol = 1 ;
____
and we are left with:
____
[5.7 * 2.104588 g ] / 22.4 = ? g ;
______________________
→ [ 11.9961516 g ] / 22.4 =
0.53554248214 g ;l
_____________________________
We round this value to: " 0.54 g " ;
→ since "5.7 L " has 2 (two) significant figures;
22.4 is an exact number conversion;
and "5.7 L" has fewer significant figures than:
" 2.104588 " ; or: " 1.00794 " .
→ as such: We round to "2 (two) significant figures."
______________________________
Hope this is helpful. Wishing you the best in your academic endeavors!
_______________________________