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Oksanka [162]
3 years ago
13

Which ordered pair is a solution to the system of inequalities?

Mathematics
1 answer:
Butoxors [25]3 years ago
5 0

For this case, what we must do is find a point that meets both inequalities.

  • <em>y> -2 </em>
  • <em>x + y <4 </em>

We have then:

For (0,4):

First inequation:

4> -2 (correct)

Second inequality:

0 + 4 <4 (incorrect)

For (1,4):

First inequation:

4> -2 (correct)

Second inequality:

1 + 4 <4 (incorrect)

For (-3,5):

First inequation:

5> -2 (correct)

Second inequality:

-3 + 5 <4 (correct)

Point (-3,5) is system solution

For (-2,-3):

First inequation:

-3> -2 (incorrect)

Answer:

Point (-3.5) is system solution

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A variety pack of snacks contains 4 pretzel bags, 3 popcorn bags and 3 cheddar cracker bags. What is the probability that someon
Svetlanka [38]

Answer:

2/15

Step-by-step explanation:

Given that :

pretzel = 4

Popcorn = 3

Cheddar cracker = 3

Total = 4 + 3 + 3 = 10

Probability = Required outcome / Total possible outcomes

Selecting with replacement :

First selection :

P(pretzel bag) = 4 / 10

Second selection :

P(pretzel bag) = 3 / 9

P(2 pretzel bags) = 4/10 * 3/9 = 12 / 90 = 2/15

5 0
3 years ago
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Answer:

4/12??

Step-by-step explanation:

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3 years ago
Turma:
Roman55 [17]
E porque ya lo use y es facil
3 0
3 years ago
In a volatile housing market, the overall value of a home can be modeled by V(x) = 210x2 – 4400x + 125000, where V represents th
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Answer:

I think a picture can explain better than me!

Step-by-step explanation:

Have a good day.

7 0
3 years ago
a six sided die is rolled 4 times in a row. What is the probability of getting 4 only on the last trial of this experiment?
hoa [83]
First, start of by saying what the probability of getting a 4 is, which is 1/6.
Now, this means the probability of not getting a 4 is 1-(1/6)=(5/6), since the total probability is 1.

After doing this, you should think about what it means to only get 4 on the last trial, the 4th trial.  It means that the probabilities of the 1st, 2nd, and 3rd trial were (5/6) each.  The 4th trial had a probability of (1/6).  So the probability would be calculated as following: ((5/6)^3*(1/6)=5^3/6^4.  You can use a calculator or your computer to find out that the probability is 125/1296.  

I hope this was helpful!
5 0
3 years ago
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