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Andrej [43]
2 years ago
10

Which function has the greatest constant of variation? A x 8 9 10 11 y 20 22.5 25 27.5 B x 1 2 3 4 y 3.2 6.4 9.6 12.8

Mathematics
2 answers:
Tpy6a [65]2 years ago
6 0

Answer:

b the answer is b

Step-by-step explanation:

Lina20 [59]2 years ago
4 0

Answer : B x 1 2 3 4 y 3.2 6.4 9.6 12.8

WE analyze the first option A

x -- y -- Difference

8 -- 20

9 -- 22.5 -- 2.5

10 -- 25 -- 2.5

11 -- 27.5 -- 2.5

From the first function we can see there is a constant difference of 2.5.

We analyze the second option B

x -- y -- Difference

1 -- 3.2

2 -- 6.4 -- 3.2

3 -- 9.6 -- 3.2

48 -- 12.8 -- 3.2

From the second function we can see there is a constant difference of 3.2

3.2 is the greatest

So second function B has the greatest constant of variation.

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find point p that divides segment AB into a 2:3 ratio. The point should be closer to A. A(-3,1) and B(3,5)
Mademuasel [1]
First, work out how much you need to add to A's x and y coordinates in order to get to point B from point A.

So (using Ax to mean x-coordinate of A, Ay the y-coordinate of A, etc):
x-difference = Bx - Ax = 3 - (-3) = 3 + 3 = 6
y-difference = By - Ay = 5 - 1 = 4

Now, if the point divides the segment AB in the ratio 2:3, then it is 2/(2+3) of the way along the line AB.

i.e. it is 2/5 of the way along the line AB.

We therefore need to add 2/5 of the x- and y-differences to point A to get point p:
px = Ax + (2/5)*(x-difference) = -3 + (2/5)*6 = -3 + 12/5 = -15/5 + 12/5 = -3/5 = -0.6
py = Ay + (2/5)*(y-difference) = 1 + (2/5)*4 = 1 + 8/5 = 5/5 + 8/5 = 13/5 = 2.6

Therefore coordinates of p are (-0.6, 2.6)
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3 years ago
A bookstore costs $90 a day to keep open, and spends $12 for each book it sells. the store charges $18 for each book it sells. I
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Total Cost in a day is TC= 90 + 12n. Profit function is P=18n. And the revenue function is R = P-TC = 18n-12n-90 = 6n-90. In a day, bookstore must sell at least 15 books, because of 6n-90=0, in order to make profit. 
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B.



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A. 2n– 1 is odd if n is positive: Since n is an integer, 2n will always be even. And an even number minus 1 is always odd. Doesn't matter if n is positive or not. So this conjecture is true.



B. 2n– 1 is always even: Once again, 2n will always be even. So 2n-1 will always be odd. This conjecture is false.



C. 2n– 1 is odd if n is even: 2n is always even, so 2n-1 will always be odd, regardless of what n is. So this conjecture is true.



D. 2n– 1 is always odd: 2n will always be even. So 2n-1 will always be odd. Once again, this conjecture is true.



Of the 4 conjectures above, only conjecture B is false. So the answer is B.
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