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lbvjy [14]
4 years ago
9

g 2. The _____ spans the distance from the _____ to the location of the applied force. moment arm; pivot point moment of inertia

; center of mass torque; center of mass None of the above
Physics
1 answer:
Alik [6]4 years ago
7 0

Answer:

The correct answer to the following question will be Option A (moment arm; pivot point).

Explanation:

  • The moment arm seems to be the duration seen between joint as well as the force section trying to act mostly on the joint. Each joint that is already implicated in the workout seems to have a momentary arm.
  • The moment arm extends this same distance from either the pivot point to just the position of that same pressure exerted.
  • The pivotal point seems to be the technical indicators required to fully measure the appropriate demand trends alongside different time-frames.

The other three choices are not related to the given situation. So that option A is the appropriate choice.

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Explanation:

Power is the product of current and voltage:

P = IV

And from Ohm's law, voltage is the product of current and resistance:

V = IR

So substituting this expression for V into the power equation:

P = I (IR)

P = I² R

4 0
3 years ago
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In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of t
navik [9.2K]

Answer:

The distance up to which they can jump is 1.5 m

Solution:

As per the question:

The extension of the legs, d = 0.600 m

Acceleration, a = 1.25\times g

where

g = acceleration due to gravity = 9.8 m/s^{2}

Now,

Let the initial velocity of the jump be v m/s

So, by the third eqn of motion:

v'^{2} = v^{2} + 2ad            (1)

where

v' = final velocity

a = acceleration

d = distance between the legs

Also, for maximum range, angle, \theta = 45^{\circ}

x = \frac{v'^{2}sin2\theta}{g}     (2)

x = maximum horizontal range

Thus, using eqn (1):

v'^{2} = 0^{2} + 2\times 1.25\times 9.8\times 0.600

v' = \sqrt(14.7) = 3.834 m/s

Now, using eqn (2):

x = \frac{14.7sin2(45^{\circ})}{9.8} = 1.5 m

7 0
4 years ago
Why is the sky blue this is a serious question about physics lol
Ymorist [56]
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Hope this helps!   :)

6 0
3 years ago
NEED HELP PLZ IM FAILING. Combustion occurs when _____. oxidation reactions are very slow oxidation reactions are so fast the su
lukranit [14]
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</span>
7 0
3 years ago
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A bicyclist maintains a constant speed of 4.00 m/s up a hill that is inclined at 10.0∘ with the horizontal. Calculate the work d
Alex

Answer:

the work done by the person W_p=2.52*10^3J

the work done by gravuty W_g=-2.52*10^3J

Explanation:

Because the velocity is constant the cyclist has to excert a force equal to the component of the weight.

F_c-F_w=0

F_w=m*g*cos(\theta)\\F_w=82.0*9.81*sin(10^o)\\F_w=140N

The work done by the person is given by:

W_p=F_c*d\\W_p=140N*18.0\\W_p=2.52*10^3J

and the work done by the gravity:

W_g=F_g*d\\W_g=-82.0*9.81*sin(10)*18.0\\\\W_g=-2.52*10^3J

8 0
3 years ago
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