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kenny6666 [7]
3 years ago
10

What do fast-twitch and slow-twitch muscle fibers share in common

Physics
1 answer:
leva [86]3 years ago
7 0

Answer:

Explanation:Slow-twitch muscle fibers support long distance endurance activities like marathon running, while fast-twitch muscle fibers support quick, powerful movements such as sprinting or weightlifting.

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Which characteristics is common to the four outer planets in out solar system ?
Lubov Fominskaja [6]
I think the answer is B
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If a lever has an input arm of 80 cm and an output arm of 20 cm, what is its ideal mechanical advantage?
Alexeev081 [22]

Answer:

16

Explanation:

6 0
2 years ago
Which of the following statements are true for magnetic force acting on a current-carrying wire in a uniform magnetic field? Che
qaws [65]

Answer:

The following statements are correct.

1. The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.

2. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.

3. The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

Wrong statements:

1. The magnetic force on the current-carrying wire is strongest when the current is parallel to the magnetic field lines.

Explanation:

6 0
3 years ago
What should be angle between force and displacement to get the maximum work​
Bas_tet [7]

Answer:

0°

Explanation:

The angle between force and displacement should be 0° in order to get the maximum work done.

 

 Work done  = Force  x dcosФ°  

  Ф is the angle between force and displacement

When Ф is zero, the maximum work done is attained

When Ф is 90, the minimum work is done, in fact, work done is 0

3 0
3 years ago
Suppose the coefficient of static friction between a quarter and the back wall of a rocket car is 0.330. At what minimum rate wo
Helga [31]

Answer:3.23 m/s^2

Explanation:

Given

\mu_s =0.330

Frictional Force is balanced by force due to car acceleration

Frictional force F_s

F_s=ma_{min}

\mu_sN=ma_{min}

\mu_s\cdot mg=ma_{min}

a_{min}=\mu_s \cdot g=0.330\times 9.8=3.23 m/s^2

6 0
3 years ago
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