Answer:
Explanation:
Given that,
The length of tension wire is 10m
L = 10m
It caries a current of 10A
I = 10A
The current is perpendicular to the magnetic field
B = 5.5 × x10⁻⁵ T.
Then, θ = 90°
The magnetic force that act on the line is?
F = i(L × B)
L × B = LB Sinθ
Where
I is the current
L is the length of the wire
B is the magnetic field
θ is the angle between the field and the direction of the length.
Then,
F = I × L × B × Sinθ
F = 10 × 10 × 5.5 × x10⁻⁵ × Sin 90
F = 5.5 × x10⁻³ N
Then, the magnetic force experience on the line is 5.5 × x10⁻³N
