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PolarNik [594]
3 years ago
15

HELP PLEASE DUE IN 3 MINUTES

Physics
1 answer:
diamong [38]3 years ago
6 0

Answer:

tectonic plate movement

Explanation:

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A satellite revolves around a planet at an altitude equal to the radius of the planet. the force of gravitational interaction be
padilas [110]
Let
M = the mass of the planet
n = the mass of the satellite.
r = the radius of the planet

When the satellite is at a distance r from the surface of the planet, the distance between the centers of the two masses is 2r.
The gravitational force between them is
f_{0} = \frac{GMm}{(2r)^{2}} = \frac{1}{4} ( \frac{GMm}{r^{2}} )
where
G =  the gravitational constant.

When the satellite is on the surface of the planet, the distance between the two masses is r.
The gravitational force between them is
f_{4} =   \frac{GMm}{r^{2}} =4f_{0}

Answer:  f_{4} = 4f_{0}

5 0
4 years ago
Read 2 more answers
A tin can is partially filled with water and heated so that the water boils for some time. Explain what happens to the can when
kozerog [31]
It gets smaller and lower in the tin can
7 0
3 years ago
How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?
tatyana61 [14]
Missing part in the text of the problem: 
"<span>Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"</span>

First we can calculate the amount of energy needed to raise the temperature of the water, which is given by
Q=m C_s \Delta T
where
m=1.8 g is the mass of the water
C_s = 4.18 J/(g K) is the specific heat capacity of the water
\Delta T=2.5 K is the increase in temperature.

Substituting the data, we find
Q=(1.8 g)(4.18 J/(gK))(2.5 K)=18.8 J=E

We know that each photon carries an energy of
E_1 = hf
where h is the Planck constant and f the frequency of the photon. Using the wavelength, we can find the photon frequency:
\lambda =  \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{3 \cdot 10^{-6} m}=1 \cdot 10^{14}Hz

So, the energy of a single photon of this frequency is
E_1 = hf =(6.6 \cdot 10^{-34} J)(1 \cdot 10^{14} Hz)=6.6 \cdot 10^{-20} J

and the number of photons needed is the total energy needed divided by the energy of a single photon:
N= \frac{E}{E_1}= \frac{18.8 J}{6.6 \cdot 10^{-20} J} =2.84 \cdot 10^{20} photons
4 0
3 years ago
After a nucleus with 85 protons undergoes alpha decay, it has<br><br> ? protons.
Valentin [98]

Answer:

After a nucleus with 85 protons undergoes alpha decay, it has  83 protons.

Explanation:

In an alpha particle there are two protons

In the given substance's nucleus, there are total of 85 protons

After the decay, the proton number reduce

The current proton number after decay is

85 -2 = 83

After a nucleus with 85 protons undergoes alpha decay, it has  83 protons.

5 0
3 years ago
What would increase the force of gravity between two objects?
yulyashka [42]
By Newton's Law of Universal Gravitation.

F =  GMm/r²

Where F is Force of Gravitation, M = Mass of first object, m = mass of second object, r = distance of separation

From the formula, you can see that if the masses, M and m, increased, the value of F would definitely increase as well.

And if r increased the value of F would be reduced because you would be dividing by a bigger number, but when the value of r is decreased the value of F would be increased, because you would then be dividing by something smaller. Note the r is at the denominator of the formula.

So F would increase if there was increase in Masses and decrease in distance.

So the answer is C. a and b.
3 0
3 years ago
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