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Flura [38]
3 years ago
15

Which of the following is a field (action-at-a-distance) force?

Physics
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

F_{grav} is a field force, as gravity does not physically apply force and does not require proximity.

Explanation:

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Verdadero o falso de La energía interna es la energía térmica asociada al objeto en virtud del movimiento de sus moléculas.
d1i1m1o1n [39]

Answer:

Es la energía cinética interna total de un objeto debido al movimiento aleatorio de sus ... a es la energía que posee un objeto o cuerpo en virtud del movimiento de sus ... Si el movimiento de estas moléculas y átomos es más rápido, se dice que el ... Por lo tanto, la energía térmica asociada con la conducción resulta de la .

Explanation:

5 0
3 years ago
An 1120 kg car traveling at 17 m/s is brought to a stop while skidding 40 m. Calculate the work done on the car by friction forc
sergij07 [2.7K]

Answer:

Approximately (-1.6 \times 10^{5}\; \rm J) (assuming that the car was on level ground.)

Explanation:

When an object of mass m is moving at a speed of v, the kinetic energy of that object would be (1/2) \, m \cdot v^{2}.

Initial kinetic energy of the car:

\begin{aligned}&\frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2}\times 1120\; \rm kg \times (17\; \rm m \cdot s^{-1})^{2} \\ &\approx 1.6\times 10^{5}\; \rm J \end{aligned}.

After the car comes to a stop, the kinetic energy of this car would be 0\; \rm J because the car would not be moving.

Change to the kinetic energy of the car: \text{Final KE} - \text{Initial KE} = -1.6 \times 10^{5}\; \rm J.

If the car is traveling on level ground, friction would be the only force that contributed to this energy change. Hence:

\text{Work of friction} = \text{Energy change} = -1.6\times 10^{5}\; \rm J.

The value of the work that friction did is negative. The reason is that at any instant before the car comes to a stop, friction would be exactly opposite to the direction of the movement of the car.

The work of a force on an object is the dot product of that force and the displacement of that object. The dot product of two vectors of opposite directions is negative. Hence, in this question, the work that friction did on the car would be negative because the friction vector would be opposite to the movement of the car.

6 0
3 years ago
What is the acceleration of the object?<br> m/s²
Orlov [11]

Answer:

-2.5m/s^2

Explanation:

10-40/12-0=-2.5

7 0
2 years ago
A T-Bar is similar to a_______
dezoksy [38]

Answer:

Donkey

Explanation:

3 0
3 years ago
A 15-µF capacitor is charged to 40 V and then connected across an initially uncharged 25-µF capacitor. What is the final potenti
Kobotan [32]

Answer:

24volts

Explanation:

If a 15-µF capacitor is charged to 40V, the charge across the capacitor can be calculated using the formula;

Q = CV where;

Q is the charge flowing across the capacitor

C is the capacitance of the capacitor. = 15-µF

V is the voltage = 40V

Q = 15×10^-6×40

Q = 0.0006coulombs

If the charge of 0.0006coulombs is then connected across an initially uncharged 25-µF capacitor, the potential difference across the 25-µF can be calculated using the initial expression;

Q = CV

V = Q/C

V = 0.0006/25×10^-6

V = 24Volts

Therefore, the final potential difference across the 25-µF capacitor will be 24volts

6 0
3 years ago
Read 2 more answers
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