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alex41 [277]
3 years ago
9

Consider the example of a positive charge q moving in the negative z-direction with speed v with the local magnetic field of mag

nitude B in the z-direction.
Find F, the magnitude of the magnetic force acting on the particle. Express your answer in terms of v, q, B, and other quantities given in the problem statement.
Physics
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

Answer:

<em>F</em> = <em>0</em>

Explanation:

This problem can be solved by using the equation for the force produced by a magnetic field over a charge

<em>F</em> = q<u><em>v</em></u> X <em>B</em>

That is, the cross product between velocity and the magnetic field.

In this case, v is in the negative z-direction <em>v</em> = -v k^,

and the magnetic field is in the positive z-direction <em>B</em> = z k^

Hence, the cross product is

F = q<em>v </em>X <em>B</em> = 0i^ - 0j^ + 0k^ = <em>0</em>

In this case the net force is zero due to both velocity and magnetic field vectors are in the z-direction

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<u>Force</u><u> </u><u>=</u><u> </u><u>mg</u><u> </u><u>=</u><u> </u><u>4</u><u>0</u><u>0</u><u>0</u><u>0</u><u>N</u>

<u>Pressure</u><u> </u><u>=</u><u> </u>

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