A force of 210 N is applied to an object and the object accelerates at 14m/s2. Determine the mass of the object in kg.
1 answer:
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Answer:
Work: 4.0 kJ, heat: 4.25 kJ
Explanation:
For a gas transformation at constant pressure, the work done by the gas is given by
where in this case we have:
is the pressure
is the initial volume
is the final volume
Substituting,
The 1st law of thermodynamics also states that
where
is the change in internal energy of the gas
Q is the heat absorbed by the gas
Here we know that
Therefore we can re-arrange the equation to find the heat absorbed by the gas:
Answer:
(a) ΔU=747J
(b) γ=1.3
Explanation:
For (a) change in internal energy
According to first law of thermodynamics the change in internal energy is given as
ΔU=Q-W
Substitute the given values
ΔU=970J-223J
ΔU=747J
For(b) γ for the gas.
We can calculate γ by ratio of heat capacities of the gas
γ=Cp/Cv
Where Cp is the molar heat capacity at constant pressure
Cv is the molar heat capacity at constant volume
To calculate γ we first need to find Cp and Cv
So
For Cp
As we know
Q=nCpΔT
Cp=(Q/nΔT)
From relation of Cv and Cp we know that
Cp=Cv+R
Where R is gas constant equals to 8.314J/mol.K
So
So
γ=Cp/Cv
γ=[(37J/mol.K) / (28.687J/mol.K)]
γ=1.3