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blondinia [14]
3 years ago
6

What is the wavelength of this wave

Physics
1 answer:
melamori03 [73]3 years ago
4 0

10 cm

you can see the distance from peak to peak or the distance between the starting point to the end of the first whole wave

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Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =
Sloan [31]

Answer:

The current is  I  = 8.9 *10^{-5} \  A

Explanation:

From the question we are told that

     The  radius is r =  3.17 \  mm  =  3.17 *10^{-3} \ m

      The current density is  J =  c\cdot r^2  =  9.00*10^{6}  \ A/m^4 \cdot r^2

      The distance we are considering is  r =  0.5 R  =  0.001585

Generally current density is mathematically represented as

          J  =  \frac{I}{A }

Where A is the cross-sectional area represented as

         A  =  \pi r^2

=>      J  =  \frac{I}{\pi r^2  }

=>    I  =  J  *  (\pi r^2 )

Now the change in current per unit length is mathematically evaluated as

        dI  =  2 J  *  \pi r  dr

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

         I  = 2\pi  \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr

         I  = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr

        I  = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ]  | \left    0.001585} \atop 0}} \right.

        I  = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]

substituting values

        I  = 2 *  3.142  *  9.00 *10^6 *   [ \frac{0.001585^4}{4} ]

        I  = 8.9 *10^{-5} \  A

5 0
4 years ago
You start at (8, 1). You move right 2 units. Where do you end?
ivann1987 [24]

I'm pretty sure should be shifting your transformation those two units to the right from the original function.

Moving right = subtracting

Moving left = adding

4 0
3 years ago
Why don't atoms get too close?
Kamila [148]

Answer:

<h3>This tends not to happen, because atoms are composed of charged particles that interact at a distance. ... Since the electrons are around the outside of the atom, those are the things that first interact, and as they have the same charge, they repel one another.</h3>

A. The electrons from atom repel each other

5 0
2 years ago
Read 2 more answers
Identify each of the quantities below as either vector or scalar
natta225 [31]

Answer:

2nd answer 3.2m/s is a scalar l, all others are vectors.

Explanation:

In order to be considered as a vector a certain quantity must have both a magnitude and a direction.

The most common example is velocity. It has both magnitude and direction, like the 1st and the last answers.

The 3rd answer is an acceleration. It is also given with its direction. So we have to consider it also as a vector.

But 2nd answer has no direction mentioned, so it is considered as a scalar.

7 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Studentka2010 [4]
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Speed = distance / time

Substitute in your values:

Speed = 720 / 8

Speed = 90

They traveled 90 miles per hour

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

8 0
3 years ago
Read 2 more answers
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