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4 years ago

Which object absorbs the most visible light?

Physics

2 answers:

klio [65]4 years ago

4 0

Answer:

C. a black t-shirt

Explanation:

wariber [46]4 years ago

3 0

<h3>Answer;</h3>

A black T-shirt 

<h3>Explanation;</h3>

Materials can be either reflectors and absorbers of waves such as light waves, sound waves etc. Reflectors are those materials that reflects waves, such that the waves bounces back on hitting the surface of those materials.
Examples of such materials are those with smooth and shiny surfaces, while those with rough and opaque surfaces are poor reflectors of light. Additionally, these materials that are good reflectors are poor absorbers while those that are poor reflectors are good absorbers of light.
Dull surfaces are the best emitters and absorbers of light but the worst reflectors of light waves. White surfaces or polished surfaces are bad and worst emitters and absorbers of light waves respectively

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A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm2 , plate separation d = 9.00 mm and dielectric constant

PIT_PIT [208]

Answer:

$9.96\cdot 10^{-10}J$

Explanation:

The capacitance of the parallel-plate capacitor is given by

$C=\epsilon_0 k \frac{A}{d}$

where

ϵ0 = 8.85x10-12 C2/N.m2 is the vacuum permittivity

k = 3.00 is the dielectric constant

$A=30.0 cm^2 = 30.0\cdot 10^{-4}m^2$ is the area of the plates

d = 9.00 mm = 0.009 m is the separation between the plates

Substituting,

$C=(8.85\cdot 10^{-12}F/m)(3.00 ) \frac{30.0\cdot 10^{-4} m^2}{0.009 m}=8.85\cdot 10^{-12} F$

Now we can calculate the energy of the capacitor, given by:

$U=\frac{1}{2}CV^2$

where

C is the capacitance

V = 15.0 V is the potential difference

Substituting,

$U=\frac{1}{2}(8.85\cdot 10^{-12}F)(15.0 V)^2=9.96\cdot 10^{-10}J$

4 0

3 years ago

When a body is moving with a uniform velocity, the acceleration is ___?

denis23 [38]

According to the formula :
a=ΔV / ΔT
When a body is moving with a uniform velocity, the acceleration is zero. That's it. You should remember, that velocity is not constant whereas speed is constant.

4 0

3 years ago

What type of System interact with its environment

Oksi-84 [34.3K]

Answer:

System management

Explanation:

8 0

3 years ago

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.9 m/s. The car is a distanc

sammy [17]

If it takes $t$ seconds to reach the car, then the distance $d$ is $3.9t$ .

The bear's distance from the tourist's starting point is
$6t-23$

For maximum $d$ , we set the equations equal to each other:
$3.9t=6t-23$
$\Rightarrow -2.1t=-23$
$\Rightarrow t=\frac{23}{2.1}$
so the distance is
$d=3.9(\frac{23}{2.1})\approx42.741\ m$

6 0

3 years ago

PLEASE HELP SOLVE THIS PHOTO BELOW

polet [3.4K]

Answer:

Explanation:

The pattern is adding .5 to the cm every .1 in weight you just continue the table

8 0

3 years ago

Read 2 more answers