1/3x - 2 = 1/4x + 11....it looks to me like one y was subbed in for another...
ur 2 equations are :
y = 1/3x - 2 and y = 1/4x + 11...but we need them in standard form...
y = 1/3x - 2
-1/3x + y = -2 ..multiply by 3
-x + 3y = -6.....or 3y - x = -6 <==
y = 1/4x + 11
-1/4x + y = 11 ...multiply by 4
-x + 4y = 44 or 4y - x = 44 <==
Answer:
Both are quadrant
Step-by-step explanation:
<h3>Given</h3>
z = 3
2y +z = 1
2x +3y +2z = 13
<h3>Find</h3>
x, y, z
<h3>Solution</h3>
... z = 3 is given
Substitute that into the second equation.
... 2y + 3 = 1
... 2y = -2 . . . . . subtract 3
... y = -1 . . . . . . . divide by the coefficient of y
Substitute these two solutions into the third equation.
... 2x +3(-1) +2(3) = 13
... 2x = 10 . . . . . . . . . . . . collect terms, subtract 3
... x = 5 . . . . . . . . . . . . . . divide by the coefficient of x
The variable values are: x = 5, y = -1, z = 3
Step-by-step explanation:
do () first
2*1-1
then multiplication
2-1
then subtraction
=1
same reason as above
4 *2 -6
8-6
=2
