A circle in the standard (x,y) coordinate plans has center C(-1,2) and passes through A(2,6). Line segment AB is a diameter of t
his circle. What are the coordinates of point B?
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Answer:
Step-by-step explanation:
I assume your equation to solve is
When we have a product of two factors equal to zero,
The solution is either A = 0 or B = 0.
In this case, this means that we can break the equation into two equations:
Solving the first one, we get:
For the second one, we rewrite it as:
And we see that this equation has two solutions:
Therefore, the three solutions are:
Given data:
The first set of equations are x+y=4, and x=6.
The second set of equations are 3x-y=12 and y=-6.
The point of intersection of first set of te equations is,
6+y=4
y=-2
The first point is (6, -2).
The point of intersection of second set of te equations is,
3x-(-6)=12
3x+6=12
3x=6
x=2
The second point is (2, -6).
The equation of the line passing through (6, -2) and (2, -6) is,
Thus, the required equation of the line is y=x-8.