The force of gravity is the
force with which massively large objects such as the earth attracts another
object towards itself. All objects of the earth exert a gravity that is
directed towards the center of the earth. Therefore, the force of gravity of
the earth is equal to the mass of the object times acceleration due to gravity and also equal to the weight of the object.
F = ma
since F = W
W = ma
Answer:
R = 33.1 m and y = 8.27 m
Explanation:
This exercise is projectile launch, let's use the scope equation to find the displacement on the X axis
R = vo2 sin 2θ / g
R = 18 2 sin (2 45) /9.8
R = 33.1 m
First let's look for the velocity components
vox = vo cos θ
voy = vo sin θ
vox = 18 cos 45
vox = 12.73 m / s
voy = 18 sin 45
voy = 12.73 m / s
To find the maximum vertical displacement, where the vertical velocity must be zero, we can use the equation
² = ² - 2 g y
0 = ² - 2 g y
y =² / 2g
y = 12.73² / (2 9.8)
y = 8.27 m
Answer:
0.8m/s
Explanation:
Weight of mas,F=763 N
Mass of man=
By using
Weight of flatcar=F'=3513 N
Mass of flatcar=
Total mass of the system=Mass of man+mass of flatcar=77.86+358.5=436.36 kg
Velocity of system=19.8m/s
Let v be the velocity of flatcar with respect to ground
Velocity of man relative to the flatcar=
Final velocity of man with respect to ground=v-4.68
By using law of conservation of momentum
Initial momentum=Momentum of car+momentum of flatcar
Initial speed of flatcar=Speed of system
Increase in speed=Final speed-initial speed=20.6-19.8=0.8m/s