3 years ago

Graph are blank a relationship

Physics

1 answer:

Maru [420]3 years ago

7 0

I have no clue sorry maybe try applying the answers and questions then I'll answer for u

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True

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3 years ago

Aparticlewhosemassis2.0kgmovesinthexyplanewithaconstantspeedof3.0m/s along the direction r = i + j . What is its angular momentu

svetoff [14.1K]

Answer:

$\vec{L}=-30\frac{kgm^2}{s}\hat{k}$

Explanation:

In order to calculate the angular momentum of the particle you use the following formula:

$\vec{L}=\vec{r}\ X\ \vec{p}$ (1)

r is the position vector respect to the point (0 , 5.0), that is:

r = 0m i + 5.0m j (2)

p is the linear momentum vector and it is given by:

$\vec{p}=m\vec{v}=(2.0kg)(3.0m/s)(\hat{i+\hat{j}})=6\frac{kgm}{s}(\hat{i}+\hat{j})$ (3)

the direction of p comes from the fat that the particle is moving along the i + j direction.

Then, you use the results of (2) and (3) in the equation (1) and solve for L:

$\vec{L}=-30\frac{kgm^2}{s}\hat{k}$

The angular momentum is -30 kgm^2/s ^k

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3 years ago