C. Electrical current increases as resistance decreases
Answer:
361.46 N
Explanation:
= Coefficient of thermal expansion = 
Y = Young's modulus for steel = 
A = Area = 
= Original length = 1.28 km
= Change in temperature = 
Length contraction is given by

Also,


The tension in the wire is 361.46 N
Answer:
a.) 490m
b.) 98m/s
Explanation:
Given that the
Acceleration g = 9.8 m/s^2
Time = 10s
Since the parachutist jumps out of an aeroplane. The parachutist jumped out from rest. Initial velocity U is therefore equal to zero. That is,
U = 0
Distance covered = height H
The height can be calculated by using second equation of motion
H = Ut + 1/2gt^2
Substitute g and t into the formula
H = 1/2 × 9.8 × 10^2
H = 490 m
Therefore, she travels as far as 490 m
b.) Her final velocity can be calculated by using third equation of motion
V^2 = U^2 + 2gH
Substitute g and H into the formula.
Remember that U = 0
V^2 = 2 × 9.8 × 490
V^2 = 9604
V = sqrt (9604)
V = 98 m/s
Therefore, her final velocity is 98 m/s
Answer:
is 3 and 2
Explanation: the firth one is 3 and the 2
Answer:
3091.56
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.81 m/s² (positive downward and negative upward)

Distance traveled in the first stage is 1093.75 m

Velocity at the end of first stage is 87.5 m/s

Acceleration of the second stage is 4.5 m/s²

Distance traveled in the second stage is 1100 m

Distance traveled after the second stage has stopped firing is 894.81 m
Total height the rocket reached = 1093.75+1100+897.81 = 3091.56 m