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maw [93]
2 years ago
13

According to x-ray observations, the space between galaxies in a galaxy cluster is?

Physics
1 answer:
crimeas [40]2 years ago
6 0

According to x-ray observations, the space between galaxies in a galaxy cluster is very hot. It is because the matter between galaxies (often called the intergalactic medium) is mostly hot, ionized hydrogen with bits of heavier elements such as carbon, oxygen and silicon thrown in.

Massive structures are collapsing than at earlier times. Large collapsing structures lead to higher velocity intergalactic shocks and, as a result, significant intergalactic shock heating, with some gas heated well above the 10^{4} K temperatures.

Heating also occurs as galaxies expel out most of the gas that fell into them. The final product is a warm/hot phase, with temperatures of > 10^{5} K.

Now, Let's know how do you use X-rays to make space observations?

X-radiation is absorbed by the Earth's atmosphere, so instruments to detect X-rays must be taken to high altitude by balloons, sounding rockets, and satellites.

To learn more about Galaxy Cluster, here

brainly.com/question/16557484

#SPJ4

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A commuter airplane starts from an airport and takes theroute. The plane first flies to city A, located 175 km away in a directi
bearhunter [10]

Answer:

245.45km in a direction 21.45° west of north from city A

Explanation:

Let's place the origin of a coordinate system at city A.

The final position of the airplane is given by:

rf = ra + rb + rc    where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:

rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km

rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km

The module of this position is:

rf = \sqrt{rfX^2+rfY^2} = 245.45km

And the angle measure from the y-axis is:

\alpha =atan(rfX/rfY) = 21.45\°

So the answer is 245.45km in a direction 21.45° west of north from city A

6 0
4 years ago
A player kicks a soccer ball in a high arc toward the opponent's goal. When the soccer ball reaches its maximum height, how does
Artyom0805 [142]

Answer:

The speed of the soccer ball at height point is less than its initial speed

Explanation:

The initial velocity of the soccer can be written in vector form as

v_{i = v cos θ î + v sin θ j

where v_{i  is initial velocity of the ball

           v is the initial speed of the ball

Assume soccer ball is kicked at an angle θ with an horizontal and initial speed vm/s. Its horizontal component will be as,

v_{x} = v cos θ

v_{y} = v sin θ

At the maximum height, the vertical component becomes zero. therefore, the velocity of the soccer at the maximum point can be written as,

v_{m} = v cos θ j

where, v_{m} is velocity of the soccer ball at maximum height

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4 years ago
Which of the following is the correct abbreviated SI unit describing the mass of an object? a. molly
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The answer is C I hope this helps

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