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disa [49]
3 years ago
13

Do you add the initial position and final position to get distance?

Physics
1 answer:
mamaluj [8]3 years ago
4 0
You can do d=st (s is speed and t is time) or you can use pythagorean theorem if the distance is or the two positions is a right angle.
You might be interested in
in the diagram, q2 is +34.4*10^-6 C, and q3 is -72.8*10^-6 C. The net force on q2 is 225 N to the right. What is q1? Include the
sesenic [268]

Answer:

  q₁ = -6.54 10⁻⁵ C

Explanation:

Force is a vector quantity, but since all charges are on the x-axis, we can work in one dimension, let's apply Newton's second law

                F = F₁₂ + F₂₃

the electric force is given by Coulomb's law

                F = k q₁q₂ / r₁₂²

let's write the expression for each force

                F₂₃ = k q₂ q₃ / r₂₃²

                F₂₃ = 9 10⁹ 34.4 10⁻⁶ 72.8 10⁻⁶ / 0.1²

                F₂₃ = 2.25 10³ N

               

                F₁₂ = k q₁q₂ / r₁₂²

                F₁₂ = 9 10⁹ q₁ 34.4 10⁻⁶ / 0.1²

                F₁₂ = q₁   3,096 10⁷ N

we substitute in the first equation

                225 = q₁  3,096 10⁷ +2.25 10³

                q₁ = (225 - 2.25 10³) / 3,096 10⁷

                q₁ = -6.54 10⁻⁵ C

4 0
3 years ago
A football player runs from his own goal line to the opposing team's goal line, returning to his forty-yard line, all in 22.4 s.
Bumek [7]
I assume L=120 yards as the length of the football field.

1) The average speed is given by the total distance covered by the player divided by the time taken.
The total distance covered to go from one goal line to the other and then back to the 40-yards line is
S=120y+(120-40)y=120y+80y=200 y
And the time taken is t=22.4 s, so the average speed of the player is
v= \frac{S}{t}= \frac{200 y}{22.4 s}=8.93 y/s

2) The find the average velocity, we should also consider the direction (and the sign) of the velocity.
In the the first part of the motion, the player goes from one goal line to the other one, so he covers 120 y. However, in the second part of the motion he goes back by 80 y. Therefore, the net displacement of the player is
S=120 y-80 y=40 y
and so, the average velocity is
v= \frac{S}{t}= \frac{40 y}{22.4 s}= 1.79 y/s
6 0
3 years ago
The photon energies used in different types of medical x-ray imaging vary widely, depending upon the application. Single dental
Alchen [17]

1. Single dental x-rays: 5.0\cdot 10^{-11}m

The energy of the photon is

E=25 keV = 25,000 eV

Using the conversion factor

1 eV=1.6\cdot 10^{-19} J

we can convert it into Joules:

E=(25,000 eV)(1.6\cdot 10^{-19}J/eV)=4\cdot 10^{-15} J

The relationship between photon energy and wavelength is

\lambda=\frac{hc}{E}

where

h=6.63\cdot 10^{-34} Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

E is the energy

Substituting into the formula, we find

\lambda=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{4\cdot 10^{-15} J}=5.0\cdot 10^{-11}m

2. Microtomography: 2.0\cdot 10^{-11} m

The energy of these photons is 2.5 times greater, so

E=(2.5)(4\cdot 10^{-15} J)=1\cdot 10^{-14} J

And by applying the same formula used at point 1, we find the corresponding wavelength:

\lambda=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{1\cdot 10^{-14} J}=2.0\cdot 10^{-11}m

6 0
3 years ago
An experiment is designed to test the relationship between the initial height of a basketball before it is dropped to the height
Virty [35]

Answer:

A. The starting height of the ball

Explanation:

When we talk about controlled variables, we refer to the variable that should be kept the same throughout the experiment. The reason why we do this, is to limit anything else that is not being tested, that may affect the results of the experiment.

In the scenario given, the experiment is to see the relationship between the <u>initial height of a basketball</u> and the <u>height of its rebound bounce. </u>

So you the starting height of the ball should vary, meaning it is NOT controlled.

3 0
3 years ago
Starting from the front door of your ranch house, you walk 50.0m due east to your windmill, and then you turn around and slowly
juin [17]

Answer:

velocity = 0.3m/s

speed = 1.21 m/s

Explanation:

The total time it takes to get from the front door to the bench is

t = 27 + 39 = 66 seconds

The net displacement from the front door to the bench is the distance from the front door to the windmill subtracted by the distance from the windmill to the bench

s = 50 - 30 = 20 m

So the average velocity is net displacement divided by total time

v = s / t = 20 / 66 = 0.3 m/s

The total distance from the front door to the bench is the sum of distance from the front door to the windmill and the distance from the windmill to the bench

S = 50 + 30 = 80 m

So the average speed is total distance divided by total time

v = s / t = 80 / 66 = 1.21 m/s

8 0
3 years ago
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