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disa [49]
3 years ago
13

Do you add the initial position and final position to get distance?

Physics
1 answer:
mamaluj [8]3 years ago
4 0
You can do d=st (s is speed and t is time) or you can use pythagorean theorem if the distance is or the two positions is a right angle.
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In a closed energy system, energy is?​
Alisiya [41]

Answer:

Explanation:

A closed system can exchange energy but not matter, with its surroundings. An isolated system cannot exchange any heat, work, or matter with the surroundings, while an open system can exchange energy and matter.

Hope this helped you!

3 0
3 years ago
Lookin for new friends hml ​
Hitman42 [59]
Okay i will hit you low
4 0
3 years ago
5. A 1052 kg truck, starting from rest, reaches a speed of 20.0 m/s in 6.20 s.
BaLLatris [955]

Answer:

a. 3,392.7 N

b. 3,392.7 N

Explanation:

We are given the following information;

  • Mass of the truck as 1052 kg
  • initial speed as 0 m/s
  • Final speed as 20.0 m/s
  • Time taken as 6.20 s

#a. We are required to calculate the acceleration;

We need to know the formula of getting acceleration;

a = (v-u)/t

Where v is the final velocity, u is the initial velocity

Therefore;

a = (20 m/s - 0 m/s)/6.20s

= 3.225 m/s²

Thus, the average acceleration of the truck is 3.225 m/s²

#b. We are required to calculate the net force on the truck

We need to know that;

According to the second Newton's law of motion, F=ma

Where F is the net force, m is the mass and a is the acceleration.

Therefore;

Net force, F = mass × Acceleration

                    = 1052 kg × 3.225 m/s²

                    = 3,392.7 N

Thus, the net force on the truck is 3,392.7 N

4 0
4 years ago
A 120-kg hollow spherical ball 1 m in diameter accelerates at a constant rate from rest to 5 rpm in 20 s and then continues to r
FromTheMoon [43]

Answer:

Explanation:

a )

moment of inertia of hollow ball

= 2 / 3  mR²  , m is mass and R is radius of the ball

= 2 / 3 x 120 x .5²

= 20 kg m²

b )

5 rpm =      5 / 60 rps

n = .0833

angular velocity ω = 2πn= 2 x 3.14 x .0833=  .523 rad /s

angular acceleration = increase in angular velocity / time

= .523 - 0 / 20

α = .02615 rad /s²

c )

Torque = moment of inertia x angular acceleration

= 20 x .02615

= .523 Nm

d )

θ = 1/2 α t²

= .5 x  .02615 x 20²

= 5.23

2π n = 5.23 where n is required number

n = .83

3 0
3 years ago
Answer all these and i'll mark brainliest.
Luda [366]
Formula for net force: force= mass x acceleration
6 0
3 years ago
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