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3 years ago

Do you add the initial position and final position to get distance?

1 answer:

4 0

You can do d=st (s is speed and t is time) or you can use pythagorean theorem if the distance is or the two positions is a right angle.

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What is the wavelenght and the frequencen of walkie-talkie?

GuDViN [60]

Nowadays, most of the walkie talkies ... and all R/C models ... operate in the "Family Radio Service" (FRS) band. That's 46-49 MHz. The wavelength is 6.12-6.52 meters.

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3 years ago

A spacecraft is separated into two parts by detonating the explosive bolts that hold them together. The masses of the parts are

nordsb [41]

Answer:

0.279 m/s

Explanation:

mass (m1) = 1150 kg

mass (m2) = 1900 kg

impulse (J) = 200 N.s

With what relative speed do the two parts separate because of the detonation?

since both parts separate, their relative speed = speed of m1 + speed of m2

speed of m1 = $\frac{J}{m}$ = $\frac{200}{1150}$ = 0.174 m/s

speed of m2 = $\frac{J}{m}$ = $\frac{200}{1900}$ = 0.105 m/s
relative speed = 0.174 + 0.105 = 0.279 m/s

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3 years ago

If a .40kg football is thrown with an acceleration of 1.8m/s^2, what is the force used to throw the football? Question 1 options

RoseWind [281]

Answer:

The correct answer is option C , 0.72 N

Explanation:

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3 years ago

What is a asexual relationship

miskamm [114]

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3 years ago

Read 2 more answers

A wrecking ball is hanging at rest from a crane when suddenly the cable breaks. The time it takes for the ball to fall halfway t

Naddik [55]

Answer:

1.697s

Explanation:

We use the second equation of free fall under gravity as follows;

$h=ut+\frac{1}{2}gt^2...............(1)$

Since the ball fell freely, u = 0m/s, therefore equation (1) reduces to

$h=\frac{1}{2}gt^2...............(2)$

Given that h is the total height the ball falls through in time t seconds.

However, according to the stated problem the ball falls halfway in 1.2s, this simply implies that the ball falls through a distance of $\frac{h}{2}$ in 1.2s. Hence we can write the following, given that $g=9.8m/s^2$ ;

$\frac{h}{2}=\frac{1}{2}*9.8*1.2^2\\hence\\h=9.8*1.2^2\\h=14.112m$

We can now proceed to find the time t for which it falls through h = 14.112m as follows;

$14.112=\frac{1}{2}*9.8*t^2\\14.112=4.9t^2\\t^2=\frac{14.112}{4.9}\\t^2=2.88\\t=\sqrt{2.88} \\t=1.697s$

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3 years ago