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NeX [460]
1 year ago
14

What is the electric field strength between two parallel plates 5cm apart with a potential difference of 25V across them?

Physics
1 answer:
Butoxors [25]1 year ago
5 0

Use the following formula for the electric field strength between two parallel plates:

E = V/d

where,

V: potential difference = 25V

d: distance between plates = 5 cm = 0.05 m

Replace the previous values of the parameters into the formula for E:

E=\frac{25V}{0.05m}=500\frac{V}{m}

Hence, the electric field strength is 500V/m

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What is the importance of star ranting labelilling of an electrical appliance?​
Misha Larkins [42]

Answer:

The standard of efficiency varies by product category

these are called BEE star label and they show how much electricity the appliance consumes in year each appliance gets btw one and five stars with five stars meaning that it's extremely efficienct andis likely to keep your electricity bills in check

<em><u> </u></em><em><u>hop</u></em><em><u>e</u></em><em><u> it's</u></em><em><u> helpful</u></em>

5 0
3 years ago
A ball with a mass of 2000 g is floating on the surface of a pool of water. What is the minimum volume that the ball could have
Doss [256]

Answer:

2000\; {\rm cm^{3}}.

Explanation:

When the ball is placed in this pool of water, part of the ball would be beneath the surface of the pool. The volume of the water that this ball displaced is equal to the volume of the ball that is beneath the water surface.

The buoyancy force on this ball would be equal in magnitude to the weight of water that this ball has displaced.

Let m(\text{ball}) denote the mass of this ball. Let m(\text{water}) denote the mass of water that this ball has displaced.

Let g denote the gravitational field strength. The weight of this ball would be m(\text{ball}) \, g. Likewise, the weight of water displaced would be m(\text{water})\, g.

For this ball to stay afloat, the buoyancy force on this ball should be greater than or equal to the weight of this ball. In other words:

\text{buoyancy} \ge m(\text{ball})\, g.

At the same time, buoyancy is equal in magnitude the the weight of water displaced. Thus:

\text{buoyancy} = m(\text{water}) \, g.

Therefore:

m(\text{water})\, g = \text{buoyancy} \ge m(\text{ball})\, g.

m(\text{water}) \ge m(\text{ball}).

In other words, the mass of water that this ball displaced should be greater than or equal to the mass of of the ball. Let \rho(\text{water}) denote the density of water. The volume of water that this ball should displace would be:

\begin{aligned}V(\text{water}) &= \frac{m(\text{water})}{\rho(\text{water})} \\ &\ge \frac{m(\text{ball}))}{\rho(\text{water})}  \end{aligned}.

Given that m(\text{ball}) = 2000\; {\rm g} while \rho = 1.00\; {\rm g\cdot cm^{-3}}:

\begin{aligned}V(\text{water}) &\ge \frac{m(\text{ball}))}{\rho(\text{water})}  \\ &= \frac{2000\; {\rm g}}{1.00\; {\rm g\cdot cm^{-3}}} \\ &= 2000\; {\rm cm^{3}}\end{aligned}.

In other words, for this ball to stay afloat, at least 2000\; {\rm cm^{3}} of the volume of this ball should be under water. Therefore, the volume of this ball should be at least 2000\; {\rm cm^{3}}\!.

3 0
1 year ago
Suppose a moving car has 2000 J of kinetic energy. If the carʹs speed doubles, how much kinetic energy would it then have?
Bond [772]

Answer:

option A

Explanation:

given,

Kinetic energy of the car = 2000 J

speed of the car is doubled

we know,

KE_1 = \dfrac{1}{2}mv^2

2000= \dfrac{1}{2}mv^2........(1)

now, speed of the car is doubled

v' = 2 v

KE_2 = \dfrac{1}{2}mv'^2

KE_2 = \dfrac{1}{2}m(2v)^2

from equation (1)

KE_2 = 4\times \dfrac{1}{2}m(v)^2

KE_2 = 4\times 2000

KE_2 = 8000\ J

Hence, the Kinetic energy would be equal to 8000 J.

The correct answer is option A.

8 0
2 years ago
What is the formula for momentum? *<br><br> p = m/v<br> f = m x a<br> f = m/s<br> p = m x v
KiRa [710]

Answer:

momentum in a body can be calculated using

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<em><u>i</u></em><em><u>e(</u></em><em><u>p</u></em><em><u>=</u></em><em><u>m×</u></em><em><u>v</u></em><em><u>)</u></em>

4 0
3 years ago
If you double the period of a pendulum. what happens to its length?​
victus00 [196]

Answer:

Time period is directly proportional to the length so if the length is doubled the time period is doubled

hope it is helpful....

5 0
3 years ago
Read 2 more answers
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