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1 year ago

What is the electric field strength between two parallel plates 5cm apart with a potential difference of 25V across them?

Physics

1 answer:

Butoxors [25]1 year ago

5 0

Use the following formula for the electric field strength between two parallel plates:

E = V/d

where,

V: potential difference = 25V

d: distance between plates = 5 cm = 0.05 m

Replace the previous values of the parameters into the formula for E:

$E=\frac{25V}{0.05m}=500\frac{V}{m}$

Hence, the electric field strength is 500V/m

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3 years ago

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2 years ago

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Answer:

$\Delta V = 1.8 \times 10^7 V$

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GIVEN

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by accelerating through a potential difference ∆V

Thus the alpha particle will

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3 years ago

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Answer:

Explanation:

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$X_c = \frac{1}{2 \pi fC}$

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Substitute into the formula:

$X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c = \frac{1}{0.0002512}\\X_c = 3,980.89$

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3 years ago