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NeX [460]
2 years ago
14

What is the electric field strength between two parallel plates 5cm apart with a potential difference of 25V across them?

Physics
1 answer:
Butoxors [25]2 years ago
5 0

Use the following formula for the electric field strength between two parallel plates:

E = V/d

where,

V: potential difference = 25V

d: distance between plates = 5 cm = 0.05 m

Replace the previous values of the parameters into the formula for E:

E=\frac{25V}{0.05m}=500\frac{V}{m}

Hence, the electric field strength is 500V/m

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Find the speed of a wave with a frequency of 18 Hz and a wavelength of 6 meters. Show work. WILL MARK BRAINLIEST IF CORRECT
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3 years ago
A compressor receives air at 290 K, 100 kPa and a shaft work of 5.5 kW from a gasoline engine. It is to deliver a mass flow rate
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Answer:

P_2=4091\ KPa

Explanation:

Given that

T₁ = 290 K

P₁ = 100 KPa

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Lets take the exit temperature = T₂

We know that

P=\dot{m}\ C_p (T_2-T_1)

5.5=0.01\times 1.005(T_2-290})\\T_2=\dfrac{5.5}{0.01\times 1.005}+290\ K\\\\T_2=837.26\ K

If we assume that process inside the compressor is adiabatic then we can say that

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\dfrac{837.26}{290}=\left(\dfrac{P_2}{100}\right)^{0.285}\\2.88=\left(\dfrac{P_2}{100}\right)^{0.285}\\

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Which statement best describes longitudinal waves?
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