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dimaraw [331]
3 years ago
6

All describe the relationship of the parts of an electrical current except: _________.

Physics
1 answer:
kaheart [24]3 years ago
6 0
C. Electrical current increases as resistance decreases
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What is the total distance the hiker walked ? A.4 km B.6 km C.10 km D.20 km/
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Answer: the answer is c

Explanation:

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Shari uses the data in the table to predict how her weight on Venus would compare with her weight on Earth.
spin [16.1K]

Answer :  <em>Her weight is lower on Venus because the acceleration due to gravity is lower.</em>

Explanation :

Venus is also called as Earth's twin. This is because both the mass and the size of Earth and Venus are almost same. The acceleration due to gravity on earth is 9.8\ m/s^2 while on Venus is 8.87\ m/s^2.

So, when Shari measure her weight on Venus she found her weight is lower on Venus. This is because the acceleration due to gravity is lower on the surface of Venus as compared to the Earth.

Since,    w=mg

i.e. weight depends on g.

<em>So, correct prediction is (b)</em>

3 0
3 years ago
Read 2 more answers
Determine the moment of inertia Ixx of the mallet about the x-axis. The density of the wooden handle is 860 kg/m3 and that of th
Yuki888 [10]

Complete Question

Diagram for this  shown on the first uploaded image

Answer:

The moment of inertia Ixx of the mallet about the x-axis is I{xx}= 0.119 kg \cdot m^2

Explanation:

From the question we are told that

        The density `of wooden handle is  \rho_w = 860 kg/m^3

        The density `of soft-metal head  is \rho_s =8000kg/m^3

Generally the mass of the wooden can be mathematically obtained with this formula

          m_w = \rho_w A_w l_w

Where A_w is mass of wooden handle which is  mathematically obtain with the formula

             A_w = \frac{\pi}{4} d^2_w

Where d_w is the diameter  of the wooden handle which from the diagram is

       27mm = \frac{27}{1000} = 0.027m

So  A_w = \frac{\pi}{4} * 0.027^2

      l_w is the length of the the wooden handle which is given in the diagram as   l_w = 315mm = \frac{315}{1000} = 0.315m

Substituting these value into the formula for mass

      m_w = 860 * (\frac{\pi}{4} * 0.027^2 ) *0.315

            = 0.155kg

Generally the mass of the soft-metal head can be mathematically obtained with this formula

           m_s = \rho_s A_s l_s

Where A_s is mass of soft-metal head which is  mathematically obtain with the formula

            A_s = \frac{\pi}{4} d^2_s

Where d_s is the diameter  of the soft-metal head which from the diagram is            

       36mm = \frac{36}{1000} = 0.036m

So  A_s = \frac{\pi}{4} * 0.036^2

 l_s is the length of the the soft-metal head which is given in the diagram

     as   l_s = 90mm = \frac{90}{1000} = 0.090m

Substituting these value into the formula for mass  

                  m_s = 8000 * (\frac{\pi}{4} * 0.036^2 ) *0.090

                       =0.733kg

Generally the mass moment of inertia about x-axis for the wooden handle is

                  (I_{xx})_w  =    [\frac{1}{3}m_w + l_w^2 ]  

Substituting values

                   (I_{xx})_w  =    [\frac{1}{3}*0.155 + 0.315^2 ]

                              =5.12*10^{-3}kg \cdot m^2  

Generally the mass moment of inertia about x-axis for the soft-metal head is

    (I_{xx})_s = [\frac{1}{12}m_s l_s ^2 + b^2]

Where b is the distance from the centroid to the axis of the head which is mathematically given as

                   b=l_w +\frac{d_s}{2}

Substituting values

                 b = 0.315 + \frac{0.036}{2}

                    = 0.336m

Now substituting values into the formula for mass moment of inertia about x-axis for soft-metal head

                            (I_{xx})_s = [\frac{1}{12} *0.733*  0.090^2 + 0.336^2]

                                      =0.113 kg \cdot m^2

Generally the mass moment of inertia about x-axis is mathematically represented as

         I_{xx} = (I_{xx})_w + (I_{xx})_s

                = [\frac{1}{3}m_w + l_w^2 ] + [\frac{1}{12}m_s l_s ^2 + b^2]

Substituting values

        I_{xx} = 5.12*10^{-3} +0.113

               I{xx}= 0.119 kg \cdot m^2

             

             

8 0
3 years ago
What is the period of a wave with the wave speed of 12m/s and a frequency of 60 hz?
aleksklad [387]
To determine the period of a wave you need not utilize the value for the wave speed. 

The formula for the period is T= 1/f
T stands for period/time while f is for frequency. Substitute the value for the frequency which is 60 Hz. That would give you:

T= 1/60 Hz

convert Hz to cycles per second to extract the unit of time (s).

60 Hz x 1/s/1 Hz=  60/s

To continue the computation:

T=1/60/s that will give you a T= 0.017 s or 17 ms.
4 0
4 years ago
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