All categories

3 years ago

All describe the relationship of the parts of an electrical current except: _________.

Physics

1 answer:

kaheart [24]3 years ago

6 0

C. Electrical current increases as resistance decreases

You might be interested in

A boy is pedaling his bicycle at a velocity of 0.20km/ minute . How far will he travel in 2.5 hours

fredd [130]

30km. 24 the first two hours and 6 the half hour

4 0

4 years ago

Read 2 more answers

A car traveling at 50 m/s comes to a stop in 5 seconds. What is the<br> acceleration of this car?

Alexandra [31]

Answer:10

Explanation:

You have to do speed divided by time so your answers 10

4 0

3 years ago

A spherical capacitor is formed from two concentric sphericalconducting shells separated by vacuum. The inner sphere has radius1

zubka84 [21]

Explanation:

(1). Formula to calculate the potential difference is as follows.

$\Delta V = -\int E dr$

= $-\int \frac{kq}{r^{2}} dr$

= $\frac{kq}{r_{f}} - \frac{kq}{r_{i}}$

= $\frac{kq(r_{f} - r_{i})}{r_{f}r_{i}}$

= $\frac{9 \times 10^{9} \times 3.30 \times 10^{-9}(0.1 - 0.015)}{0.1 \times 0.015}$

= 38.7 volts

Therefore, magnitude of the potential difference between the two spheres is 38.7 volts.

(2). Now, formula to calculate the energy stored in the capacitor is as follows.

E = $\frac{1}{2}QV$

= $\frac{1}{2} \times 3.30 \times 10^{-9} \times 3.87 V$

= $6.39 \times 10^{-8} J$

Thus, the electric-field energy stored in the capacitor is $6.39 \times 10^{-8} J$ .

7 0

3 years ago

Read 2 more answers

If 2050 J of heat are added to a 150 g object its temperature increases by 15°C.

Darina [25.2K]

When an object gets heated by a temperature ΔT energy needed, E = mcΔT

Here energy is given E = 2050 J

Mass of object = 150 g

Change in temperature ΔT = 15 $^0C$ = 15 K

a) Heat capacity of an object equal to the ratio of the heat added to (or removed from) an object to the resulting temperature change.

So heat capacity = E/ΔT = 2050/15 = 136.67 J/K

b) We have E = mcΔT

c = $\frac{2050}{150*10^{-3}*15} = 911.11 J/kgK$

So object's specific heat = 911.11 J/kgK

5 0

3 years ago

When a satellite is a distance R from the center of the Earth, the force of gravity on the satellite is F. What is the gravitati

Lubov Fominskaja [6]

Gravitational force on a satellite is given by the formula

$F = \frac{GMm}{r^2}$

now here we know that force on the satellite is F when its distance from center of Earth is R

Now the distance from the center of earth will be 3R so the force is given as

$F' = \frac{GMm}{(3R)^2}$

$F' = \frac{GMm}{9R^2}$

so if we compare it with initial value of force then it is

$F' = \frac{F}{9}$

so correct answer is

$(1) F/9$

7 0

3 years ago

Read 2 more answers