By definition, we have that the work done is given by:
Where,
F: force in the direction of displacement
d: displaced distance
Substituting values we have:
Then, the power is given by:
Where,
t: time
Substituting values we have:
Answer:
The work done on the box is 100 Nm, and the power is 20 Nm/s.
Answer:
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Explanation:
Explanation:
<em>a)Which of the two has uniform acceleration?</em>
Acceleration is the second derivative of position. The acceleration of the first particle is:
x = 4t² − 2t
v = 8t − 2
a = 8
The acceleration of the second particle is:
x = 6t³ + 8t
v = 18t² + 8
a = 36t
The first particle has uniform acceleration.
<em>b)Which one is likely to come to rest at some time during its motion?</em>
The particles come to rest when v = 0. The first particle's velocity has a real zero at t = 4. The second particle's velocity has only imaginary zeros, meaning v is never 0.
Answer:
6667.9 J
Explanation:
We are given that
Mass of cannon.m=14 kg
Time,t=3.15 s
Initial velocity,u=0
We have to find the work done by gravity on the falling cannon ball.
Substitute the values
Work done,W=mgh
Using the formula
Time - 0.792s
acceleration - 9.8m/s2
vertical height - ?
remember that height is in meters
so from the acceleration
9.8 = x
----
0.792*0.792
cross multiply
=6.147m approximately 6.2m
