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Artemon [7]
3 years ago
15

What percent of 97 is 11?

Mathematics
1 answer:
saveliy_v [14]3 years ago
5 0
97% of 11 is:

 Answer:10.67
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Find the area of the semicircle. diameter = 12
dimaraw [331]

Answer:

\huge\boxed{\sf Area\ of \ Semicircle = 56.55 \ units^2}

Step-by-step explanation:

Diameter = 12

Radius = 12/2 = 6

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\sf Area\ of \ Semicircle = 56.55 \ units^2

7 0
3 years ago
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Study the following quote. Then answer the question that follows.
nlexa [21]
A. People accused of crimes had certain rights unless found guilty through legal process.

8 0
3 years ago
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I need help with exercises 3,4, and 6 please show all work and don’t answer number 5 just tell me if it is correct
joja [24]
*If you need me to do #5, DM me!

3. 
The area of a triangle can be given by (just plug and chug as always):
A_t = \frac{1}{2} bh = \frac{1}{2}(3)(4) = 6ft^2
The area of the triangle is 6ft².

4. I will divide into a triangle and a rectangle (because the actual equation for the area of a pentagon requires it to be a perfect pentagon). Let's do the triangle first (height is 3 because you subtract 12 from 15):
A_t = \frac{1}{2} bh = \frac{1}{2}(8)(3) = 12m^2
A_r = bh = 12(8) = 96m^2
Now we just add them:
96+12 = 108m^2

So, the area of that pentagon is 108m².

5. You are actually wrong on this one because the area of a triangle is:
A_t = \frac{1}{2}bh
So, just halve your answer and it will be correct.

6. We can just split it into 4 triangles of equal area and then multiply the area of 1 triangle by 4 to get the total area. Let's do just that:
A_t = \frac{1}{2}bh = \frac{1}{2}(2.5)(5) = 6.25cm^2
Multiply by 4 to get total area:
6.25*4 = 25cm^2

So, the area of the given rhombus is 25cm².
8 0
3 years ago
Giving brainlist to whoever answers
SpyIntel [72]

Answer:

144m2

Step-by-step explanation:

I think very carefully on my brain is it cirrect?

3 0
3 years ago
Which value of a in the exponential function below would cause the function to shrink? f(x) = a(three-halves) Superscript x Four
Natalka [10]

Answer:

Four-fifths

Step-by-step explanation:

As we know that

By multiplying the function by a constant, we may expand or shrink the function in the y-direction.

Now we have

y=a(b^{x})

if a> 1  > the function would enlarge

if 0< a < 1 > the function would shrinks

Now

For case A

a = \frac{4}{5}

0 < (\frac{4}{5} )< 1 ....... > the function would shrinks

For case B

a = \frac{5}{4}

(\frac{5}{4} )>1 .......> the function would enlarge

For case C

a = \frac{3}{2}

(\frac{3}{2} )>1 .........> the function would enlarge

For case D

a = \frac{7}{4}

(\frac{7}{4} )>1 .........> the function would enlarge

Therefore the second option is correct

5 0
3 years ago
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