The energy of a photon is given by
E = h × v
where:
E is the energy in joules/photon
'h' is the constant 6.63 × 10⁻³⁴
'v' is the frequency 7.55 × 10¹⁴
Substitute 'h' and 'v' into the formula we have
E = (6.63×10⁻³⁴) × (7.55×10¹⁴)
E = (6.63×7.55) × (10⁻³⁴ × 10¹⁴)
E = 50.0565 × 10⁽⁻³⁴⁺¹⁴⁾
E = 50 × 10⁻²⁰ joules/photon
In order to find the answer you will have too divide 58 by 18 and then divide what you get from that by 100 to get your answer.
100%/x%=58/18
(100/x)*x=(58/18)*x
100=3.22222222222*x
(3.22222222222) to get x
100/3.22222222222=x
x=31.0344827586
Therefore your answer is "31%."
Hope this helps.
Answer:
C.It is a one-tailed test since the alternative hypothesis states that the parameter is greater than the hypothesized value.
Step-by-step explanation:
Let p be the percentage of students enrolled in an introductory Chemistry class dropped before the midterm. Then null and alternative hypotheses are:
: p=10%
: p>10%
The alternative hypothesis states that the parameter is greater than the hypothesized value.
Given:
a. 35% of 150 g
b. 113% of $55
To find:
The correct values for the given blanks.
Solution:
a. 35% of 150 g
Here, the percent part is 35% and percent whole is 100%.
35% of 150 g is:

So, the number part is 52.5 g and the whole number is 150 g.
Therefore, the percent part is 35%, number part is 52.5 g and the whole number is 150 g.
b. 113% of $55 g
Here, the percent part is 113% and percent whole is 100%.
113% of $55 is:

So, the number part is $62.15 and the whole number is $55.
Therefore, the percent part is 113%, number part is $62.15 and the whole number is $55.
Answer:
(
,0)
Step-by-step explanation: