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2 years ago

Find the equation of the line that passes through the points (-2, 3) and (1, -6). Write your answer in Standard Form.

Mathematics

1 answer:

dlinn [17]2 years ago

7 0

Slope = (-6 - 3)/(1+2) = -9/3=-3
y - 3 = -3(x +2)
y - 3 = -3x - 6
3x + y = -3
answer is 3x + y = -3 (third one)

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A central angle of a circle measures π/3 radians intercepts an arc that is 12πcm. What is the radius of the circle?

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2 years ago

The perimeter of a rectangle is 24 inches. Find the dimension If the length of the rectangle is 3 inches more than it’s width.

GuDViN [60]

Answer:

length is 7.5 and width is 4.5

Step-by-step explanation:

Its given that perimeter of the triangle is 24 units.

The condition is that length is 3 units more than the width.

l=w+3;

Formula for perimeter is 2(l+w).

so ,

2(w+w+3)=24,

2w+3=12,

w=4.5,

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2 years ago

The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches. Men the same

masha68 [24]

Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

Step-by-step explanation:

Let x and y area the random variable that represents the heights of women and men.

Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.

i.e. $\mu_1 = 64$ $\sigma_1=2.7$

Since , $z=\dfrac{x-\mu}{\sigma}$

Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).

[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]

$z=\dfrac{72-64}{2.7}=2.96296296\approx2.96$

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.

i.e. $\mu_2 = 69.3$ $\sigma_2=2.8$

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).

[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

$z=\dfrac{70-69.3}{2.8}=0.25$

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

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2 years ago