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Archy [21]
3 years ago
15

I need the middle one

Mathematics
2 answers:
viva [34]3 years ago
4 0

Answer:

8

Step-by-step explanation:

1 min = 4/3

4/3 × 6 = 8

the answer is 8

USPshnik [31]3 years ago
3 0

Answer:

8

Step-by-step explanation:

divide 15 by y 2.5 and then 20 by 2.5 and get 8 so thats your answer

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Solve the inequality.<br><br><br> 16 &lt; k + 10
Len [333]
 The answer is k=<span>160..............</span>
6 0
3 years ago
Mr. McKay wrote an algebra test with a total of 15 questions consisting of multiple choice and short response style questions. M
tankabanditka [31]

Step-by-step explanation:

x = number of multiple choice questions

y = number of short response questions

x + y = 15

5x + 10y = 100

=>

x + 2y = 20

let's subtract the first from the second equation :

x + 2y = 20

- x + y = 15

--------------------

0 y = 5

x + y = 15

x + 5 = 15

x = 10

to graph you need to consider both equations as linear functions. and you need to transform them into e.g. a slope intercept form : y = ax + b

a is the slope, b is the y- intercept.

x + y = 15

transforms to

y = -x + 15

this line goes e.g. through the points (0, 15) and (1, 14).

and

x + 2y = 20

transforms to

2y = -x + 20

y = -x/2 + 10

this line goes e.g through (0, 10) and (2, 9).

the crossing point of both lines is the solution and should therefore be the point (10, 5) as calculated above.

5 0
3 years ago
6.24 x 10-5 - 4.091 x 103 =
castortr0y [4]
Is the 10 taking away 5 or was it meant to me 10.5 ?
6 0
3 years ago
Read 2 more answers
A 12-meter ladder leans against a building forming a 30° angle with the building.
KatRina [158]

Answer:

will show you two (2) ways to solve this problem.

A diagram is needed to see what is going on....

 

Without loss of generality (WLOG)

The wall is on the right. The ladder leans against the wall

with a POSITIVE slope, from SW to NE (quadrant 3 to quadrant 1).

The measure from the bottom of the ladder to the wall is 6.

 

 

Option 1:

 

The ladder, ground and wall form a right triangle.

 

The hypotenuse (ladder) is 14 feet.

 

 The bottom of the ladder is 6 feet from the wall,

  so the base of this right triangle is 6 feet.

 

The top of the ladder to the ground represents

the missing leg of the right triangle.

 

The pythagorean theorem applies, which says

 6^2 + h^2 = 14^2   where h is the height

                                 of the top of the ladder to the ground

 

36 + h^2 = 196

 

 h^2 = 196 - 36

 

h^2  = 160

 

h = sqrt(160)

 

   = sqrt(16 * 10)

 

    = sqrt(16)* sqrt(10)

 

    = 4*sqrt(10) <--- exact answer

 

    = 4 * 3.16227766016838....

 

     = 12.64911....

 

    12.65 <--- rounded to 2 digits as directed

 

----------------------------------------------

Option #2: using trig

 

With respect to the angle formed by the bottom of the

ladder with the ground

  cos T = 6/14 = 3/7  

 T = inverse-cosine(3/7) = 64.623006647 degrees

 

 sin(64.623006647) = h/14

 

 h = 14*sin(64.62300647) = 12.6491106 <--- same answer                        

hope this helps

Step-by-step explanation:

5 0
3 years ago
The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of app
AfilCa [17]

Answer:

Q(t) = 4.5(1.013)^{t}

The world population at the beginning of 2019 will be of 7.45 billion people.

Step-by-step explanation:

The world population can be modeled by the following equation.

Q(t) = Q(0)(1+r)^{t}

In which Q(t) is the population in t years after 1980, in billions, Q(0) is the initial population and r is the growth rate.

The world population at the beginning of 1980 was 4.5 billion. Assuming that the population continued to grow at the rate of approximately 1.3%/year.

This means that Q(0) = 4.5, r = 0.013

So

Q(t) = Q(0)(1+r)^{t}

Q(t) = 4.5(1.013)^{t}

What will the world population be at the beginning of 2019 ?

2019 - 1980 = 39. So this is Q(39).

Q(t) = 4.5(1.013)^{t}

Q(39) = 4.5(1.013)^{39} = 7.45

The world population at the beginning of 2019 will be of 7.45 billion people.

6 0
3 years ago
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