Recall that the median of a set of numbers is the number in the middle of the set, after the numbers have been rearranged from lowest to highest.
From the plot, we get that the number, arranged from lowest to highest are:

The number in the middle of the above set is:

Therefore the median of the given numbers is:

Answer: 42.
Answer:
It would possibly be 6/10
Step-by-step explanation:
hope i had it right
Answer: (A) vertical asymptote: x = 2, horizontal asymptote: y = 1
<u>Step-by-step explanation:</u>

<u>Vertical Asymptote</u> is the restriction on the x-value. The denominator cannot be zero, so x - 2 ≠ 0 ⇒ x ≠ 2
The restricted value on x is when x = 2 <em>which is the vertical asymptote</em>
<u>Horizontal Asymptote</u> (H.A.) is the restriction on the y-value. This is a comparison of the numerator (n) and denominator (m). There are 3 rules that will help you:
- n > m No H.A. (use long division to find slant asymptote)
- n = m H.A. is the coefficient of n divided by coefficient of m
- n < m H.A. is 0
In the given problem, n < m so y = 0, however there is also a vertical shift of up 1 so the H.A. also shifts up. This results in H.A. of y = 1
Answer:
A
Step-by-step explanation:
To answer this, we need to see what happens to the curves on the given interval
For f(x), we have that there is a decrease as we are moving from a higher positive value of y to a lower positive value of y over the specified interval
For g(x), we can see that we are moving from a lower positive y value to a higher positive y value
What this mean is that the first option is correct