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Luda [366]
3 years ago
13

How much cheaper per ounce is purchasing 7 ounces for $7.84 compared to purchasing 5 ounces for $5.70

Mathematics
1 answer:
WARRIOR [948]3 years ago
7 0
7.84/7 = $1.12
5.70/5 = $1.14
1.14 - 1.12 = .2
2 cents cheaper
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There are 165 children taking swimming lessons at the pool . If 10 children will be assigned to each instructor, how many instru
olchik [2.2K]
Okay so 165 kids 
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just divide 165 by 10 ? 
8 0
3 years ago
Construct the 95% confidence interval for the population mean using the appropriate distributions. a. A random sample of 50 peop
SSSSS [86.1K]

Answer: 95% confidence interval would be (26.01,29.39).

Step-by-step explanation:

Since we have given that

n = 50

Mean = 27.7

Standard deviation = 6.12

We need to construct 95% confidence interval for the population.

so, z = 1.96

So, it becomes,

\bar{x}\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=27.7\pm 1.96\times \dfrac{6.12}{\sqrt{50}}\\\\=27.7 \pm 1.69\\\\=(27.7-1.69,27.7+1.69)\\\\=(26.01,29.39)

Hence, 95% confidence interval would be (26.01,29.39).

4 0
3 years ago
Kim purchased a dress for $132 which was on sale for 60% of its original price. What was
Sophie [7]
Multiply .6 x 132 and that gets you 79.2 then you add 132 +79.2 =$211.20
6 0
3 years ago
Read 2 more answers
Ezra is training for a track race. He starts by sprinting 100 yards. He gradually increases his distance, adding 5 yards a day f
Sergeu [11.5K]
On the 21st day, he sprints 205 yards.

Is that what you meant for the problem

or do u want to know how many yards he sprinted total for the 21 days
If it is,
he sprinted a total of 3390 yards
4 0
4 years ago
Read 2 more answers
find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}
inn [45]
Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
And x² - 10x - 11=0

Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2  and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2      and  x" = [10 - √64]/2

x' = (10+12)/2    and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity


6 0
3 years ago
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