Answer:
Neither is affected
Explanation:
The reaction occurs as follows:
K₂Cr₂O₇ + Pb(NO₃)₂ → PbCr₂O₇ + 2K⁺ + 2NO₃⁻
That means per mole of reaction you will have two moles of both K⁺ and NO₃⁻.
But volume is also doubled, doing that concentration of spectator ions doesn't change.
Right answer: Neither is affected
I hope it helps!
The concentrations of a mixture at equilibrium are constant as a function of time because the <span>e forward reaction proceeds at the same rate as the reverse reaction.</span>
<span>Each silver quarter has .18 troy ounces of silver. So, my calcs say about 5 1/2 quarters to the troy ounce (silver).</span>
<h2>
Answer: 8.69 × 10⁻¹ Hz
</h2>
<h3>
Explanation:
</h3>
Frequency = Speed of Light ÷ Wavelength
= (2.99 × 10⁸ m/s) ÷ (3.44 × 10⁻⁸ m)
= 8.69 × 10⁻¹ Hz
The frequency of a light of wavelength 34.4 nm is 8.69 × 10⁻¹ Hz.
<u>Notes:</u>
Hz ≡ /s
1 m = 10⁹ nm
Hello!
When NaOH is added to a buffer composed of CH₃COOH and CH₃COO⁻, the following reactions happen:
-First, the NaOH is neutralized by CH₃COOH:
NaOH + CH₃COOH → H₂O + CH₃COONa
-Second, the CH₃COONa dissociates in its ions:
CH₃COONa → CH₃COO⁻ + Na⁺
-Finally, CH₃COO⁻ (a weak base) reacts with water to form OH⁻ ions and regenerate CH₃COOH
CH₃COO⁻ + H₂O ⇄ CH₃COOH + OH⁻
By this sequence of reactions, the buffer can mitigate the effect of the strong base added.
Have a nice day!
